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3 years ago

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The sixth grade class went to a family fun center. out of the 154 students, 85 played laser tag. A total of 80 students roller s

kates and 39 of those played laser tag.

2 answers:

Fudgin [204]3 years ago

8 0

Answer:

Whats the question?

Step-by-step explanation:

zimovet [89]3 years ago

8 0

Answer:

What’s the question for the problem?

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The area of a triangular plot with a base of 5 yards and a height of 8 yards is 20 square yards. What is the area of the triangu

pshichka [43]

Answer:

i think 60

Step-by-step explanation:

because the area in square yards is 20 and there are 3 ft in a yard so you would multiply 20 by 3 and you get 60

6 0

3 years ago

Yoshi multiplied -6.2 by -0.14. His result was -0.868. Which statement likely describes the error he made in his calculation?

Digiron [165]

Step-by-step explanation:

The answer is letter B. Negative and Negative is Positive.

3 0

2 years ago

PLEASE HELP FAST!! Lake Alice is filled with alligators and turtles. The number of turtles is 16 less than 3 times the number of

san4es73 [151]

Answer:

72 alligators, 128 turtles

Step-by-step explanation:

When you put the words into the form of an equation, with a being alligators, you get

3a-16=200

So you have to do 'letters left numbers right'. This gives you

3a=216

Now you have to divide. 216 divided by 3 equals 72. So there are 72 alligators. 200 minus 72 equals 128, so there are 128 turtles

7 0

2 years ago

Read 2 more answers

A recent poll of 80 randomly selected Californians showed that 38% ( = 0.38) believe they are doing all that they can to conserv

Elanso [62]

The margin of error given the proportion can be found using the formula

$z* \sqrt{ \frac{p(1-p)}{n} }$

Where
$z*$ is the z-score of the confidence level
$p$ is the sample proportion
$n$ is the sample size

We have
$z*=2.58$
$p=0.38$
$n=80$

Plugging these values into the formula, we have:
$2.58 \sqrt{ \frac{0.38(1-0.38)}{80} } =0.14$

The result 0.14 as percentage is 14%

Margin error is 38% ⁺/₋ 14%

8 0

3 years ago

Read 2 more answers

The article on the next page from the San Francisco Chronicle, January 27, 1996, describes very serious problems of subsidence,

Mekhanik [1.2K]

Answer:

246.3%

the complete question is found in the attached document

Step-by-step explanation:

1st step:

using 1936 data,

w1= 356% = 3.56(356/100) , H= 79 feet

specific gravity = 2.65

Sₓ= 100%= 1

initial void ratio(e₀)= (w1 x specific gravity)/Sₓ

=3.56 x 2.65/1 = 9.434

2nd step

using 1996 data

ΔH= 22ft

ΔH/H = Δe/(1 + e₀)

22/79 = Δe/(1+9.434)

0.278=Δe/10.434

Δe= 0.278 x 10.434

Δe= 2.905

Δe= e₀ - eₓ

eₓ= e₀-Δe

eₓ= 9.434 - 2.905

eₓ= 6.529

3rd step

calculating water content in 1996

eₓ =6.529, specific gravity= 2.65, Sₓ= 100%

W2 X 2.65 = 1 x 6.529

w2 = 6.529/2.65 = 2.463 = 246.3%

6 0

3 years ago