3 years ago

Find the mistake. How would you solve this problem correctly? plz answer btw those a minus this is due at 11: 59

Mathematics

1 answer:

garik1379 [7]3 years ago

4 0

Answer:

The mistake is in the second "problem" or the second part

Step-by-step explanation:

solve correctly by using pemdas when there are parenthesis but only "one" number (4) and a variable (x) you multiple (bring over the 6 and times both) leaving you with 6x + 24

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Solve This Using The Quadratic Formula: 3x^2+9x-6=0

aivan3 [116]

<h3>Therefore either $x = \frac{-3+\sqrt{17}}{2}$ or, $x = \frac{-3-\sqrt{17}}{2}$ </h3>

Step-by-step explanation:

$3x^2 +9x -6=0$ $x = \frac{-b\pm\sqrt{b^2- 4ac} }{2a}$

$\Leftrightarrow x = \frac{-9\pm\sqrt{9^2- 4.3(-6)} }{2.3}$ here a = 3 ,b = 9 and c= -6

$\Leftrightarrow x = \frac{-9\pm\sqrt{153} }{6}$

$\Leftrightarrow x = \frac{3(-3\pm\sqrt{17}) }{6}$

$\Leftrightarrow x = \frac{-3\pm\sqrt{17}}{2}$

Therefore either $x = \frac{-3+\sqrt{17}}{2}$ or, $x = \frac{-3-\sqrt{17}}{2}$

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