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3 years ago

Find the mistake. How would you solve this problem correctly? plz answer btw those a minus this is due at 11: 59

Mathematics

1 answer:

garik1379 [7]3 years ago

4 0

Answer:

The mistake is in the second "problem" or the second part

Step-by-step explanation:

solve correctly by using pemdas when there are parenthesis but only "one" number (4) and a variable (x) you multiple (bring over the 6 and times both) leaving you with 6x + 24

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Hi again here's the picture

pshichka [43]

Answer:

Step-by-step explanation:

Given,

D = diameter of semicircular part = 42 m

L = Length of straight part = 110 m

Now, let's find the perimeter:

= 2 ( length of semi-circle + length of straight part )

$= 2( \frac{\pi \: d}{2} + l)$

Plug the values

$= 2( \frac{3.14 \times 42}{2} + 110)$

Calculate the product

$= 2( \frac{131.88}{2} + 110)$

Divide

$= 2 (65.94 + 110)$

Calculate the sum

$= 2 \times 175.94$

Calculate

$= 351.88 \: m$

Hope this helps..

Best regards!!

8 0

3 years ago

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What is equivalent to this equation 4^x+3=64

Umnica [9.8K]

<span><span> x-4/x3-64</span> </span>Final result :<span> x4 - 64x3 - 4 ————————————— x3 </span>

4 0

3 years ago

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Nichol walks at a constant pace of 1.2 m/s and takes 15 minutes to get to school.

liraira [26]

Answer:

The difference between the distances they walked is 600 meters.

Step-by-step explanation:

Let's calculate the distance traveled by Nichol and Sakura with the following equation:

$d = v*t$

Where:

v: is the speed

t: is the time

The distance traveled by Nichol is:

$d_{n} = 1.2 m/s*15min*\frac{60 s}{1 min} = 1080 m$

And the distance traveled by Sakura is:

$d_{s} = 1.4 m/s*20 min*\frac{60 s}{1 min} = 1680 m$

Hence, the difference between the distances they walked is:

$d_{t} = d_{s} - d_{n} = 1680 m - 1080 m = 600 m$

Sakura traveled 600 meters more than Nichol.

Therefore, the difference between the distances they walked is 600 meters.

I hope it helps you!

4 0

3 years ago

How to solve 3+5 (c+3)=-17

BlackZzzverrR [31]

3 + 5(c + 3) = -17

First, subtract 3 from both sides. / Your problem should look like: $5(c + 3) = -17 - 3$
Second, simplify -17 - 3 to get -20. / Your problem should look like: $5(c + 3) = -20$
Third, divide both sides by 5. / Your problem should look like: $c + 3 = -\frac{20}{5}$
Fourth, simplify $\frac{20}{5}$ to 4. / Your problem should look like: $c + 3 = -4$
Fifth, subtract 3 from both sides. / Your problem should look like: $c = -4 - 3$
Sixth, simplify -4 - 3 to get -7. / Your problem should look like: $c = -7$

Answer: c = -7

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3 years ago

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When rotating a figure, which is equivalent to a 1/4 -turn counterclockwise rotation?

levacccp [35]

360 clockwise / 4 = 90 clockwise

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3 years ago

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