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Nookie1986 [14]
4 years ago
7

-9x-3y= -2 3x-y= -4 Solve for x and y.

Mathematics
1 answer:
Alexxx [7]4 years ago
4 0
Try it on the app photomath

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1. A principal of $6,325 is placed in an account that earns 3.5% interest. If the interest is
valkas [14]

Answer:

4 years and 0.035 yw

4 0
3 years ago
Please view picture. also please twll me how u got the answer
ruslelena [56]
The triangles ABC and DEC are similar triangles. We can prove this using the AA similarity theorem (angle A & angle D are congruent right angles; angle ACB & angle DCE are congruent vertical angles)

Because they are similar triangles, we can form the proportion below and solve for x to get...
AC/CD = BC/CE
2/5 = 3.61/x
2*x = 5*3.61
2*x = 18.05
2*x/2 = 18.05/2
x = 9.025
So EC is roughly 9.025 miles long

This means,
distance from Marc's house to Lewis's house = length of BE
distance from Marc's house to Lewis's house = (length of BC) + (length of EC)
distance from Marc's house to Lewis's house = (3.61) + (9.025)
distance from Marc's house to Lewis's house = 12.635

So the answer is choice D) 12.62 as this is the closest value to 12.635

6 0
4 years ago
ASAP If you chose Equilateral Equiangular Triangle Rotation to prove SAS Congruence, use the coordinates of your rotation to sho
Grace [21]

Answer:

diagram and the SAS Congruence Postulate to prove the two triangles are congruent. Explain Henry's mistake. LOGICAL REASONING Decide whether enough information is given to prove that the triangles are congruent. If there is enough information, tell which congruence postulate you would use.

Step-by-step explanation:

Hope it helps out

4 0
3 years ago
What is the answer, please help
lord [1]
Sheeeshhhhh drop out lol
3 0
3 years ago
Read 2 more answers
Find the unit vector that has the same direction as the vector v. v = 3i + j
Alchen [17]
\bf \textit{unit vector for \underline{v}}\qquad v=\ \textless \ a,b\ \textgreater \ \implies \stackrel{unit~vector}{\cfrac{a}{\sqrt{a^2+b^2}}~,~\cfrac{b}{\sqrt{a^2+b^2}}}\\\\
-------------------------------\\\\
v=3i+j\implies v=\ \textless \ 3,1\ \textgreater \ \implies \stackrel{unit~vector}{\cfrac{3}{\sqrt{3^2+1^2}}~,~\cfrac{1}{\sqrt{3^2+1^2}}}
\\\\\\
\left( \cfrac{3}{\sqrt{10}}~,~\cfrac{1}{\sqrt{10}} \right)
5 0
3 years ago
Read 2 more answers
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