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3 years ago

What are the values of a1 and r of the geometric series?

Mathematics

2 answers:

serg [7]3 years ago

7 0

Answer:

the answer is c on edg

Step-by-step explanation:

igor_vitrenko [27]3 years ago

5 0

A1 or just a as it is in the equations is just the initial term of the sequence. In this case a1=1

r is the common ratio which is that constant ratio found by dividing any term by the term preceding it...

In this case r=3/1=9/3=27/9=etc=3

So a1=1 and r=3, C. is your answer.

You might be interested in

A printer toner company launches a new product. The number of pages that this new toner can print is normally distributed with a

Vitek1552 [10]

Answer:

Step-by-step explanation:

Since the number of pages that this new toner can print is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = the number of pages.

µ = mean

σ = standard deviation

From the information given,

µ = 2300 pages

σ = 150 pages

the probability that this toner can print more than 2100 pages is expressed as

P(x > 2100) = 1 - P(x ≤ 2100)

For x = 2100,

z = (2100 - 2300)/150 = - 1.33

Looking at the normal distribution table, the probability corresponding to the z score is 0.092

P(x > 2100) = 1 - 0.092 = 0.908

2) P(x < 2200)

z = (x - µ)/σ/√n

n = 10

z = (2200 - 2300)/150/√10

z = - 100/47.43 = - 2.12

Looking at the normal distribution table, the probability corresponding to the z score is 0.017

P(x < 2200) = 0.017

3) for underperforming toners, the z score corresponding to the probability value of 3%(0.03) is

- 1.88

Therefore,

- 1.88 = (x - 2300)/150

150 × - 1.88 = x - 2300

- 288 = x - 2300

x = - 288 + 2300

x = 2018

The threshold should be

x < 2018 pages

4 0

3 years ago

American households increasingly rely on cell phones as their exclusive telephone service. It is reported that 50.4% of American

OLga [1]

The variance of the binomial distribution of the number of households with landline service is 2.

<h3>What is the binomial probability distribution?</h3>

It is the probability of <u>exactly x successes on n repeated trials, with p probability</u> of a success on each trial.

The variance of the distribution is given by:

V(X) = np(1 - p)

In this problem, the parameters are given as follows:

n = 8, p = 0.504.

Hence the variance is given by:

V(X) = 8 x 0.504 x 0.496 = 2.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

5 0

1 year ago

Can someone help me out ? Don't just guess the answer :(

Monica [59]

1) 2m+6 / m² + 7m - 12 + (m+2)/(m+4)

= 2(m+3) / (m+4)(m+3) + (m+2)/(m+4)

= 2/(m+4) + (m+2)/(m+4)

= 2+m+2 / (m+4)

= m+4 / m+4

= 1 [ Option A ]

Answer 2) 3/ (x+4) + 7/ (x-3)

= 3(x-3) + 7(x+4)/ (x² +x - 12)

= 3x-9 + 7x + 28 / (x² +x - 12)

= 10x + 19 / (x² +x - 12) [ Option A ]

Hope this helps!

5 0

3 years ago

Read 2 more answers

What is 3/5 divided by 7/9

Daniel [21]

3/5(divided)9/7
3/5x7/9
27/35

6 0

3 years ago

Assume that the population of human body temperatures has a mean of 98.6 degrees F and a standard deviation of 0.62 degrees F. I

dimulka [17.4K]

Answer:

0% probability of getting a mean temperature of 98.2 degrees F or lower.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 98.6, \sigma = 0.62, n = 106, s = \frac{0.62}{\sqrt{106}} = 0.06$