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3 years ago

4y-9=15 what does y equal

Mathematics

1 answer:

blsea [12.9K]3 years ago

4 0

Add 9 to both sides
4y -9 + 9 = 15 + 9
4y = 24
Divide by 4
4y/4 = 24/4
Solution: y = 6

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The sum of two consecutive even numbers is 98. Find the two numbers.

Rashid [163]

Answer:

48 and 50

Step-by-step explanation:

Divide 98 by 2,when you get your answer which is 49,you look for the even numbers before 98 and after 98 which is 48 and 50.When you add the two,you should get 98.

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3 years ago

Solve for the given variable 3(2x+5)=4x+21

Nookie1986 [14]

Answer:

x=3

Step-by-step explanation:

3(2x+5)=4x+21

6x+15=4x+21

-4x -4x

2x+15= 21

-15 -15

2x=6

2 2

<h2>x=3 Hope that helped!!!!</h2>

6 0

3 years ago

How can I find out how to divide 1/2

borishaifa [10]

Divide one half by what
IF your talking about this
100 divided by 1/2 then it would be 50 and all i did was put the multiply 100 by .5

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3 years ago

Read 2 more answers

PLZ NEED AN ANSWER FAST WORTH 5 TO 10 POINTS

worty [1.4K]

n - 12 = -9

Add 12 to both sides to isolate the variable n.

n = -9 + 12

n = 3

B) n = 3

4 0

3 years ago

Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1

Alenkasestr [34]

Answer:

$x=\frac{4*(2+e)}{e-2}$

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

$log(\frac{1}{x} )=-log(x)$

$log(x*y)=log(x)+log(y)$

Therefore:

$log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1$

Now, cancel logarithms by taking exp of both sides:

$e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e$

Multiply both sides by $(x-4)^{2}$ and using distributive propierty:

$2x^{2} -32=16e-8ex+ex^{2}$

Substract $16e-8ex+ex^{2}$ from both sides and factoring:

$-(x-4)*(-8-4e-2x+ex)=0$

Multiply both sides by -1:

$(x-4)*(-8-4e-2x+ex)=0$

Split into two equations:

$x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0$

Solving for $x-4=0$

Add 4 to both sides:

$x=4$

Solving for $-8-4e-2x+ex=0$

Collect in terms of x and add $4e+8$ to both sides:

$x(e-2)=4e+8$

Divide both sides by e-2:

$x=\frac{4*(2+e)}{e-2}$

The solutions are:

$x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}$

If we evaluate x=4 in the original equation:

$log(0)-log(0)=1$

This is an absurd because log (x) is undefined for $x\leq 0$

If we evaluate $x=\frac{4*(2+e)}{e-2}$ in the original equation:

$log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1$

Which is correct, therefore the solution is:

$x=\frac{4*(2+e)}{e-2}$

6 0

3 years ago