Question

You may remember that the perimeter of a rectangle is P=2(W+L) where W is the width and L is the length. Suppose that the perimeter of a rectangle is 44 feet, and the length is 12 feet more than the width. Find the width of the rectangle, in feet.

Answer 1

Answer:The width of the rectangle is 5 feet.

Step-by-step explanation:

Let w represent the width of the rectangle.

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(W + L)

where W is the width and L is the length.

If the length of the rectangle is 12 feet more than the width, the expression would be

L = W + 12

Suppose that the perimeter of a rectangle is 44 feet, it means that

2(W + L) = 44

Dividing both sides of the equation by 2, it becomes

W + L = 22 - - - - - - - - - - - -1

Substituting L = W + 12 into equation 1, it becomes

W + W + 12 = 22

2W + 12 = 22

2W = 22 - 12 = 10

W = 10/2

W = 5