the answer is b shift 2 cause the mean of shift to equals 40.4
we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
<h3>How many more inches of snow were on the ground at 5:00 p.m. than at 8:00 a.m.?</h3>
We know that at 8:00 a.m. there were t inches of snow in the ground.
At 5:00 p.m. there were 3t inches of snow in the ground.
Then the difference between the heights of the snow is:
3t- t = 2t
And we know that at 5:00 p.m. there were 12 inches of snow then we can solve the linear equation for t:
3t = 12in
t = (12in)/3 = 4 in
Replacing that in the difference of heights:
2t = 2*4in = 8in
From this, we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
If you want to learn more about linear equations:
brainly.com/question/1884491
#SPJ1
Answer:
The correct pair of functions is the third one: h(x)=(x−24)^2 and g(x)=x2
Step-by-step explanation:
Example: If we have q(x) = x^2 and its graph, moving the vertex of this graph 24 units to the right results in r(x) = (x - 24)^2.
The correct pair of functions is the third one: h(x)=(x−24)^2 and g(x)=x2
Note: the fourth pair is incorrect, because the " + " sign moves the graph of x^2 24 units to the left.
Answer:
x = -10; x = 7
Step-by-step explanation:
|2x + 3| - 6 =11
Add 6 to each side.
|2x + 3| = 17
Apply the absolute rule: If |x| = a, then x = a or x = -a.
(1) 2x + 3 = 17 (2) 2x + 3 = -17
Subtract 3 from each side
2x = 14 2x = -20
Divide each side by 2
x = 7 x = -10
<em>Check:
</em>
(1) |2(7) + 3| - 6 = 11 (2) |2(-10) + 3| - 6 = 11
|14 + 3| - 6 = 11 |-20 + 3| - 6 = 11
|17| - 6 = 11 |-17| - 6 = 1
1
17 - 6 = 11 17 - 6 = 11
11 = 11 11 = 11
1 inch =2.5cm
lenght =30.25×2.5=75.625cm
width = 21×2.5=52.5cm
area of painting = 75.625×52.5=3970.3125cm²
