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Assoli18 [71]
3 years ago
10

I need help please!!!!

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
4 0
9. Divide -6 by 2 and then square it. -3^2=9
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Can some one please help me ???!
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Of the last three chapters tests given in a computer programming class, 11 students passed all three tests , 9 students passed t
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Step-by-step explanation:

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The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of
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p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}, for r_{1} = 0

Step-by-step explanation:

The general form of quintic-order polynomial is:

p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f

According to the statement of the problem, the polynomial has the following roots:

p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)

Then, some algebraic handling is done to expand the polynomial:

p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)

p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x

If r_{1} = 0, then:

p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}

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Step-by-step explanation:

8 0
3 years ago
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