Explanation:
1)Mass of CO when 210.3 g of Fe produced.
Number of moles of 
in 210.3 g=
According to reaction, 2 moles of Fe are obtained from 3 moles of CO, then 3.76 moles of Fe will be obtained from : 
of CO that is 5.64 moles.
Mass of CO in 5.64 moles =
2)Mass of CO when 209.7 g of Fe produced.
Number of moles of in 209.7 g=
According to reaction, 2 moles of Fe are obtained from 3 moles of CO, then 3.75 moles of Fe will be obtained from : 
of CO that is 5.625 moles.
Mass of CO in 5.625 moles =
The weighted average atomic mass of Silicon is 28.1
(27.98 x .9223) + (28.98 x .0468) + (29.97 x .0309)
= 25.81 + 1.36 + .93
= 28.1
Answer:
The type of collision is A. Inelastic collision.
Explanation:
The macroscopic collisions are generally inelastic and do not conserve the kinetic energy, although of course the total energy is conserved. The inelastic collision is one in which the objects that collide remain together after the collision.
So, a figure skater skating across ice, who grabs another skater and brings him along the ice with her is a clear example of inelastic collision.
Mass of Gold = 267.165 × 0.01552494829
⇒ 4.1477228099
The amount of heat(q) required to raise m grams of a substance-specific C from T1 to T2 is given by
q=m C (T2-T1) ........1
Given : q= 2.1200 J
the initial temperature of gold, T1 = 22.0Celcius
the final temperature of gold, T2 = 1064.4Celcius
specific heat of gold = 0.131
putting values in eq 1:
⇒ 2.1200 = m × 0.131 × (1064.4-22)
⇒ 2.1200 = m × 0.131 × 1042.4
⇒ 2.1200 / 136.5544
⇒ 0.01552494829
Since 1g= 0.01552494829 Pounds
Mass of Gold = 267.165 × 0.01552494829
⇒ 4.1477228099
Learn more about temperature here: brainly.com/question/11464844
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Answer:
6.1 cm³
Explanation:
To solve this problem we first need to keep in mind <em>Archimedes' principle</em>:
- The volume of water (or any fluid) displaced by a submerged object is equal to the object's volume.
With that in mind we <u>calculate the volume of the granite piece in mililiters</u>:
- Volume displaced = 47.6 mL - 41.5 mL = 6.1 mL
- Volume of the granite piece = 6.1 mL
Given that one cubic centimeter is equal to one mililiter, the volume of the granite piece in cm³ is 6.1 cm³.
