Answer:
the reducing agent is the Na ion, therefore the Na ion is oxidised. The oxidising agent is Cl ion, therefore the Cl ion is reduced.
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Well, the molar mass of acetone would be
3(12.011)+6(1.008)+15.999 , which cleans up to be 58.08 grams.
out of this total, 3(12.011), or 36.033 grams are carbon
So, to find the percent, you do part over whole
36.033/58.08, which equals 0.6204 with significant figures
multiply that by 100 to get 62.04%
Hope that helps!
