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Mariulka [41]
3 years ago
13

The lab setup shows four test tubes. Tube 1 contains water only. Tube 2 contains a live snail. Tube 3 contains a live green wate

r plant. Tube 4 contains both a live green water plant and a live snail.
In this setup, which tubes contain at least one organism carrying on cellular respiration?
A) Tubes 1 and 2 only.
B) Tubes 2 and 4 only.
C) Tubes 3 and 4 only.
D) Tubes 2, 3, and 4 only.

Biology
1 answer:
Minchanka [31]3 years ago
4 0

Answer:

D

Explanation:

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The primary electron acceptor in photosystem II is __________. Group of answer choices P700 P700 P680 P680
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Answer:

680

Explanation:

When the P680 special pair of photosystem II absorbs energy, it enters an excited (high-energy) state. Excited P680 is a good electron donor and can transfer its excited electron to the primary electron acceptor, pheophytin.

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Lamarck wrote an important book talking about
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Lamarck's Theory of Inheritance of Acquired Characteristics was about how organisms could change during their lifetime to adapt to their environments, and how those newly acquired characteristics could be passed down to offspring.
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3 years ago
The ABO blood group assorts independently of the Rhesus (Rh) blood group and the MN blood group. Three alleles, IA , IB , and i,
Eva8 [605]

Answer:

Part 1:

The mother’s genotype is ii, rr, MN

The father’s genotype is IAIA/IAi, Rr, MM

Part 2:

Approximately 1/32 (3.125%) of children can be expected to have the stated blood types.

Explanation:

Part 1:

The mother has blood types 0, Rh- and MN. Therefore, her genotype has to be ii, rr, MN.

The father has ABO type A. His ABO genotype may therefore be either IAIA or IAi, as both are compatible with type A offspring with a type 0 mother. His Rh genotype must be rr, since his Rh- child necessarily has to have inherited one r allele from each parent. Finally, his MN genotype has to be MM since both alleles are codominant.

Part 2:

Using the given data, we build the following Punnett chart:

                IA R N     IA r N     i R N     i r N    

IA R M

IA R N

IA r M

IA r N

IB R M

IB R N

IB r M                                                    X

IB r N                                                              

Note that, of all 32 possible combinations, only a single one of them (marked with “X” produces a genotype which matches the desired blood type, as follows:

genotype: IBi, rr, MN

blood type: B, Rh-, MN

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3 years ago
The total number of genes present in a population is...
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<span>The total number of genes present in a population is called the gene pool. Hope this helps </span>
7 0
3 years ago
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Which factors would explain this pattern among predator and prey populations in this area?
Dimas [21]
I believe the Answer would be B because they are both increasing but I am not 100% correct
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3 years ago
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