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motikmotik
4 years ago
15

Determine all numbers at which the function is continuous. Picture provided below

Mathematics
1 answer:
Ne4ueva [31]4 years ago
5 0

Answer:

Choice D

Step-by-step explanation:

The function will be continuous everywhere except where the function in the denominator is 0. We, therefore determine the value(s) of x for which the function will be 0;

x^{2} -6x+8=0\\x^{2} -2x-4x+8=0\\x(x-2)-4(x-2)=0\\(x-4)(x-2)=0\\x=4\\x=2

Therefore, the points x= 2 and x =4 are points of discontinuity

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