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3 years ago

A box containing a present is shown.

Mathematics

2 answers:

Zinaida [17]3 years ago

8 0

The answer is:

D. 44in2

Anna [14]3 years ago

7 0

Answer:

82 in²

Step-by-step explanation:

Surface area =

2(5.5x4) in² + 2(5.5x2) in² + 2(4x2) in²

= 44 in² + 22 in² + 16 in²

= 82 in²

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Shoutout to aaronrogerz369 for correcting his mistake. He will be proud to tell his parents that he grew smarter.

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Needing help with problems 1,2,3. and 4

Marrrta [24]

1 and 2 are 1/4 and 90 degrees
3. 360 degrees and 4/4
4. 180 degrees and 2/4

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3 years ago

Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.

Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

Step 1

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

Step 2

Using the distance formula

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given E(-2,3), F(1,6)

$|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given F(1,6), G(4,3)

$|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given G(4,3), H(1,0)

$|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}$

Given E (−2, 3), H (1, 0)

$|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}$

Step 3

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|= $\frac{6-3}{1+2} =\frac{3}{3}=1$

Segment GH, G (4, 3), H (1, 0)

Slope of |GH| $= \frac{0-3}{1-4} =\frac{-3}{-3}=1$

Step 4

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH| $= \frac{0-3}{1+2} =\frac{-3}{3}=-1$

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| $=\frac{3-6}{4-1} =\frac{-3}{3}=-1$

Step 5

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

Step 6

Segment EF, segment FG, segment GH, and segment EH are congruent.

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

Step 7

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

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3 years ago

Read 2 more answers

5x+7y=31 , 3x-5y=21??

nikklg [1K]

Answer:

yes

Step-by-step explanation:

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3 years ago

What is the best description of a quadrilateral with four right angles?

lisov135 [29]

Square would be the best answer

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3 years ago

Hello, happy Friday, I am just here with some geometry questions.

stealth61 [152]

Answer:

m<D = 105

Step-by-step explanation:

So, Triangle STU and DEF are similar triangles, because their corresponding side lengths have the same ratio.

For example FD can be multiplied by 2.5 to get SU, and EF can be multiplied by 2.5 to get TU, and ED can me multiplied by 2.5 to get 15.

Anyways, since the two triangles are similar, they have the same angle measures, meaning that angle D can be found by subtracting 46 and 25 from 180 degrees to find the missing angle, which is 105 degrees. I hope that helps.

7 0

3 years ago

Read 2 more answers