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2 years ago

What is the answer I need it plzz

Mathematics

2 answers:

BartSMP [9]2 years ago

4 0

Answer:

(2,3,4)

Step-by-step explanation:

olasank [31]2 years ago

3 0

Answer:

Step-by-step explanation:

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Θ is in Quadrant III and cos^2 0= 1/4

pychu [463]

I think you mean to say $\cos^2\theta=\dfrac14$ . If $\theta$ is in the third quadrant, then $\sin\theta$ and $\cos\theta$ . Recall that

$\sin^2\theta+\cos^2\theta=1\implies\sin\theta=\pm\sqrt{1-\cos^2\theta}$

We expect $\sin\theta$ to be negative, so we take the negative root. We end up with

$\sin\theta=-\sqrt{1-\dfrac14}=-\dfrac{\sqrt3}2$

We also know to expect $\cos\theta$ , so

$\cos\theta=\pm\sqrt{\dfrac14}\implies\cos\theta=-\dfrac12$

By definition, we have

$\cot\theta=\dfrac{\cos\theta}{\sin\theta}$

and so

$\cot\theta=\dfrac{-\frac12}{-\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

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3 years ago

Expand and simplify 9a+3(8-2a).

Zina [86]

9a + 24 - 6a
3a + 24
In bold is your answer

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3 years ago

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What is the probability of rolling a 2 or a 5 on a six-sided number cube?

frutty [35]

Answer:

1/6 or one sixth

Step-by-step explanation:

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3 years ago

Brainlist and 40 points

Alex_Xolod [135]

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3 years ago

Find the distance between the points (<br> -<br> 10,12) and (15,12).

Nitella [24]

The distance formula is:

$d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

We are given two points in the form (x,y), so plug in the values to the distance formula:

$d= \sqrt{(-10-15)^2-(12-12)^2}$

Next we can simplify. We know that 12-12 is 0, so we can drop it from the equation, as it will not affect our answer. Also, we know that -10-15 is -25:

$d= \sqrt{(-25)^2}$

The square and square root cancel each other out leaving us with 25.

The answer is 25.

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3 years ago