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mojhsa [17]
3 years ago
11

28÷(11-7+3)×2 how do you do this

Mathematics
2 answers:
Andreas93 [3]3 years ago
7 0
You do the brackets first, 11-7=4,4+3=7 then you divide 7 by 28 which is 4. 7,14,21,28. So you now do 4x2=8 so the answer is 8.
(I checked with a calculator afterwards and I was right.)
Akimi4 [234]3 years ago
3 0
You solve the (    ) and the result is divided <span>÷ 28 times 2</span>
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Answer:

(D) 30pi inches

Step-by-step explanation:

First, we use the given volume, the given height, and the formula of the volume of a cylinder to find the radius of the base. Then we use the radius of the base to find the circumference of the base.

volume = \pi r^2 h

volume = 6750 \pi~in.^3

We set the formula equal to the volume and replace h with 30 in.

\pi r^2 h = 6750 \pi~in.^3

\pi r^2 \times 30 ~in. = 6750 \pi~in.^3

Divide both sides by 30pi in.

r^2 = 225 ~in.^2

Take the square root of each side.

\sqrt{r^2} = \sqrt{225 ~in.^2}

r = 15~in.

The radius of the base is 15 in.

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What is 5 x 5 x 5 x 5 in exponential notation?
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Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

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x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

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3 years ago
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