I think that she started with 10.. I'm not 100% sure, though
A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:
n!/((n-r)!r!)
In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.
5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5
5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10
5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10
5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5
Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.
Now we add together the combinations
1 + 5 + 10 + 10 + 5 + 1 = 32 choices combinations to discard.
The answer is 32.
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Note: There is also an equation for permutations which is:
n!/(n-r)!
Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.
We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.
I hope this helps! If you have any questions, let me know :)
Answer:
All of them
Step-by-step explanation:
if you divide 24 by 8 the you would get 3 and if you divide 24 by 4 them you will get 6 and if you divide 24 by 3 you will get 8
Answer:
The probability is 
Step-by-step explanation:
From the question we are told that
The number of green marbles is 
The number of red marbles is 
The number of red marbles is 
Generally the total number of marbles is mathematically represented as
Generally total number of marbles that are not red is
=> 
=> 
The probability of the first ball not being red is mathematically represented as
=> 
The probability of the second ball not being red is mathematically represented as
=> 
(the subtraction is because the marbles where selected without replacement )
=> 
The probability that the first two balls is not red is mathematically represented as
=> 
=> 
The probability of the third ball being red is mathematically represented as
(the subtraction is because the marbles where selected without replacement )
=> 
Generally the probability of the first two marble not being red and the third marble being red is mathematically represented as
=>
Answer:
domain is basically x and range is y, so -2,5 -2 is domain and 5 is range
Step-by-step explanation:
