Answer:
6/3 or 2 (you should probably write 2 though)
(there’s a couple notes in the pic too that will help you with slopes)
Answer:
Explanation:
<u>1. Using the minimun number of sheets of paper in the interval [300, 400]</u>
a) Cost: $ 2.00 / 100 sheets
b) 300 sheets / day × $ 2.00 / 100 sheets = $ 6.00 / day
c) Approimately 20 school days per month:
- $ 6.00 / day × 20 day = $ 120.00
<u>2. Using the maximum number of sheets of paper in the interval [300, 400]</u>
a) Cost: $ 2.00 / 100 sheets
b) 400 sheets / day × $ 2.00 / 100 sheets = $ 8.00 / day
c) Approimately 20 school days per month:
- $8.00 / day × 20 day = $ 160.00
<u>3. Middle value:</u>
Calculate the middle value between $160.00 and $120.00
- [$120.00 + $160.00] / 2 = $140.00
Thus, the answer is the option A.
We are told that the first term is 2. The next term is 7(2) = 14; the third term is 7(14) = 98. And so on. So, the first term and the common ratio (7) are known.
The nth term of this geometric series is a_n = 2(7)^(n-1).
Check: What is the first term? We expect it is 2. 2(7)^(1-1) = 2(1) = 2. Correct.
What is the third term? We expect it is 98. 2(7)^(3-1) = 2(7)^2 = 98. Right.<span />
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identity
sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x
Given
sin²x + 7cosx + 17
=1 - cos²x + 7cosx + 17
= - cos²x + 7cosx + 18 ← factor out - 1 from each term
= - (cos²x - 7cosx - 18)
Consider the factors of the constant term (- 18) which sum to give the coefficient of the cosx term (- 7)
The factors are - 9 and + 2, thus
= - (cosx - 9)(cosx + 2) ← in factored form
