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Margaret [11]
3 years ago
12

Square root of 48a^5 *b over square root of 12ab. Simplified

Mathematics
1 answer:
borishaifa [10]3 years ago
4 0
\frac{\sqrt{48a^5b}}{\sqrt{12ab}}=\frac{\sqrt{16\times3}\cdot a^{\frac{5}{2}}\cdot b^{\frac{1}{2}}}{{\sqrt{4\times3}}\cdot a^{\frac{1}{2}}b^{\frac{1}{2}}}=\frac{4\sqrt{3}\cdot a^{\frac{5}{2}}}{{2\sqrt{3}}\cdot a^{\frac{1}{2}}}=2a^{\frac{5}{2}-\frac{1}{2}}=2a^2
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Answer:

- 2b^2 + 34ab + 5a - 1

Step-by-step explanation:

<em>here's</em><em> your</em><em> solution</em>

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<em>=</em><em>></em><em> </em><em>b^</em><em>2</em><em> </em><em>+</em><em> </em><em>9</em><em>a</em><em>b</em><em> </em><em>+</em><em> </em><em>5</em><em>a</em><em> </em><em>-</em><em> </em><em>3</em><em>b</em><em>^</em><em>2</em><em> </em><em>+</em><em> </em><em>2</em><em>5</em><em>a</em><em>b</em><em> </em><em>-</em><em> </em><em>1</em>

<em>=</em><em>></em><em> </em><em>-</em><em> </em><em>2</em><em>b</em><em>^</em><em>2</em><em> </em><em>+</em><em> </em><em>3</em><em>4</em><em>a</em><em>b</em><em> </em><em>+</em><em> </em><em>5</em><em>a</em><em> </em><em>-</em><em> </em><em>1</em>

<em> </em><em> </em><em> </em><em> </em>

<em> </em><em> </em><em>hope</em><em> it</em><em> helps</em>

6 0
2 years ago
find the circumference of a circle that has an area of 452.16 square meters. (Use 3.1416 as the value of π.)
IceJOKER [234]
(1) circumference of a circle = 2π.R
(2) area of a circle = π.R²

Area = 452.16 m² (given), so we can calculate the radius:
452.16 = π.R²
452.16/π = R²

143.92 = R²  → R =√143.92 ≈ 12 m
Having R = 12, now we can calculate the circumference :

circumference of a circle = 2π.R = 2.π.12 = 75.41 m

3 0
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Step-by-step explanation: Simplify your expression and there is your answer.  

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This is for Graphing
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7 0
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