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OLEGan [10]
3 years ago
7

Engh

Mathematics
1 answer:
Gennadij [26K]3 years ago
7 0

Answer:

7m

Step-by-step explanation: bc i said

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QUESTIONNNNNNNNNN!!!!
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4 i think

Step-by-step explanation:

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2 years ago
13. A jeweller bought an engagement ring for €1200 and
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Answer:

CP of ring = 1200

profit % = 15%

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The steps for determining the center and radius of a circle using the completing the square method are shown below:
Fudgin [204]
The answer is option c.
 That is, the wrong step in step 6. It was written that the center of the circunference is the point (2.1). However, the general equation of a circumference is:
 (X- (a)) ^ 2 + (Y- (b)) ^ 2 = r ^ 2
 Where the point (a, b) is the center of the circle.
 So for this case the point for the center is: (-2, -1)
7 0
3 years ago
Matthew makes 5 apple pies for every 3 blueberry pies last week Matthew made 15 blueberry pies how many apple pies did he make
KIM [24]

Answer:

25

Step-by-step explanation:

5:3

3*5=15

This means that 5 apple pies times 5.

5*5=25

<u>25</u>:15

3 0
3 years ago
2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):
zlopas [31]
<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)

First pair of opposite sides:

<u>Slope:</u>

\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}

Second pair of opposite sides:

<u>Slope:</u>

\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\

So the diagonals measure the same, therefore this is a rectangle.

5 0
3 years ago
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