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lesantik [10]
3 years ago
15

Two mechanics worked on a car. The first mechanic worked for 15

Mathematics
1 answer:
nevsk [136]3 years ago
5 0

Answer: For the sum of 130

First: $90

Second: $40

Step-by-step explanation:

We write equations for each part of this situation.

<u>The Total Charge</u>

Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.

<u>The Sum of the Rates</u>

Since the first's rate is a and the second is b, we can write a+b=130 since their sum is 130.

We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.

For a+b=130, rearrange to b=130-a and substitute into 15a+5b=1550.

15a + 5 (130-a)=1550

15a+650-5a=1550

10a+650-650=1550-650

10a=900

a=$90 was charged by the first mechanic.

We substitute to find the second mechanic's rate.

90+b=130

90-90+b=130-90

b= $40 was charged by the second mechanic

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2

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(

1

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2

=

a

(

1

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3

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2

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f

(

x

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=

−

1

2

(

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−

3

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2

+

4

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2

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x

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2

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2

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2

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4 0
3 years ago
Please help! (image is for question 3)
nika2105 [10]

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Sn= (n-2) 180°

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Leviafan [203]

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