Rasheed need to save $235. To earn money, he plans to wash cars and charge $12 for each. Enter two estimates Rasheed could use t
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We'll say that months = n.
Make a set of the DVD's sold:
In month 1, Aaron sold 20 DVDs. There is no data for month 0.
There is a constant increase of 30 DVDs every month. We can make an equation out of this to fit this data set:
a represents the DVDs made.
We need to subtract 10 in this equation, as the starting point is 20, and the increase of 30 is different from the increase from n = 0 to n = 1.
We are looking for the amount of DVDs Aaron sold on the 13th month. Plug 13 into the equation:
The predicted number of DVDs Aaron will sell on the 13th month is 380.
Make a set of the DVD's sold:
In month 1, Aaron sold 20 DVDs. There is no data for month 0.
There is a constant increase of 30 DVDs every month. We can make an equation out of this to fit this data set:
a represents the DVDs made.
We need to subtract 10 in this equation, as the starting point is 20, and the increase of 30 is different from the increase from n = 0 to n = 1.
We are looking for the amount of DVDs Aaron sold on the 13th month. Plug 13 into the equation:
The predicted number of DVDs Aaron will sell on the 13th month is 380.
Remember
(ab)/(cd)=(a/c)(b/d)
and
1kg=1000g=1*10^3g
hmm, I estimate, 4 of them
x=number of attoms
mass of 1 times x=1*10^3
3.95*10^-22 times x=1*10^3
divide both sides by 3.95*10^-22
x=
=
=
a million has 9 zeroes
so 24 zeroes is alot that is a <span>septillion, so there are 2.5316 septillion uranium atoms in 1kg
a. 4
b. underestimate
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(ab)/(cd)=(a/c)(b/d)
and
1kg=1000g=1*10^3g
hmm, I estimate, 4 of them
x=number of attoms
mass of 1 times x=1*10^3
3.95*10^-22 times x=1*10^3
divide both sides by 3.95*10^-22
x=
a million has 9 zeroes
so 24 zeroes is alot that is a <span>septillion, so there are 2.5316 septillion uranium atoms in 1kg
a. 4
b. underestimate
</span>