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Paha777 [63]
3 years ago
11

Which choice has the same equation in both forms?

Mathematics
1 answer:
Soloha48 [4]3 years ago
5 0

Answer:

8x + 4y = 12 &   y = -2x + 3 are the same equations.

Step-by-step explanation:

To know which choice has the same equation in both forms, we need to transform the standard form into the slope intercept form.

Then, solving for y in the first equation, we get:

8x + 4y = 12\\8x + 4y - 8x = 12 -8x\\4y=12-8x\\\frac{4y}{4}=\frac{12-8x}{4} \\y=3 - 2x\\y=-2x+3

It means that 8x + 4y = 12 &   y = -2x + 3 are the same equations.

At the same way, we get that:

  • 6x + 3y = 18 &  y = 2x + 6  are not the same equation:

6x + 3y = 18\\6x + 3y - 6x = 18-6x\\3y=18-6x\\\frac{3y}{3}=\frac{18-6x}{3} \\y=6 - 2x\\y=-2x+6

  • 2x + 4y = 8  &   y = -2x + 2 are not the same equation:

2x + 4y = 8\\2x + 4y -2x= 8-2x\\4y=8-2x\\\frac{4y}{4}=\frac{8-2x}{4}\\  y=2-\frac{1}{2}x

  • 3x + 4y = 12 &  y = ¾x + 3 are not the same equation:

3x + 4y = 12\\3x + 4y -3x= 12-3x\\4y=12-3x\\\frac{4y}{4}=\frac{12-3x}{4}\\  y=3-\frac{3}{4}x

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Answer:

if im understanding right, answer is 207

Step-by-step explanation:

1000 + 1000 = 2000

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3 years ago
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Answer:

0.362

Step-by-step explanation:

When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:

- Red ball is drawn from the 1st urn with a probability of 9/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this case to happen is (9/10)*(1/6) = 9/60 = 3/20 or 0.15. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 5 blue)/(8 red + 1 blue + 5 blue) = 6/14 = 3/7.

- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14

- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7

- Blue ball is drawn from the 1st urn with a probability of 1/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this event to happen is (1/10)*(1/6) = 1/60. The probability that a ball drawn randomly from the third urn is blue given this scenario is (5 blue)/(9 red + 5 blue) = 5/14.

Overall, the total probability that a ball drawn randomly from the third urn is blue is the sum of product of each scenario to happen with their respective given probability

P = 0.15(3/7) + 0.75(5/14) + (1/12)*(2/7) + (1/60)*(5/14) = 0.362

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3 years ago
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Answer:

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Step-by-step explanation:

See the attached file for the worked solution.

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asambeis [7]

Answer:

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Step-by-step explanation:

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Answer:

2nd answer choice

Step-by-step explanation:

One way of doing this problem is to switch over to fractional exponents first.

The given product can be thought of as a square:

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