11. How many different ways can the 16 numbered pool balls be placed in a line on the pool table?
1 answer:
Answer:
The number of ways are 16! or 20,922,789,888,000.
Step-by-step explanation:
Consider the provided information.
We need to determine the number of different ways 16 numbered pool balls be placed in a line on the pool table.
For the first place we have 16 balls.
For the second place we have 15 balls left.
Similarly for the third place we have 14 balls as two balls are already arranged and so on.
Or we can say that this is the permutation of 16 things taking 16 at a time.
Thus the number of ways are: or
Hence, the number of ways are 16! or 20,922,789,888,000.
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<u>Given</u>:
Given that the bases of the trapezoid are 21 and 27.
The midsegment of the trapezoid is 5x - 1.
We need to determine the value of x.
<u>Value of x:</u>
The value of x can be determined using the trapezoid midsegment theorem.
Applying the theorem, we have;
where b₁ and b₂ are the bases of the trapezoid.
Substituting Midsegment = 5x - 1, b₁ = 21 and b₂ = 27, we get;
Multiplying both sides of the equation by 2, we have;
Simplifying, we have;
Adding both sides of the equation by 2, we get;
Dividing both sides of the equation by 10, we have;
Thus, the value of x is 5.