Answer: We accept H₀
There is not convincing evidence that the mean contents of cola is less thanthe advertised
Step-by-step explanation:
Our case normal distribution, with σ = 3
The sample is of 6 then n = 6
The calculated mean from given data is : 299.03
sgnificanc level: α = 0.05
Then H₀ null hypothesis μ₀ = 300
the alternative hypothesis μₐ < 300
As n < 30 we have to go to t table we look fr α = 0.05 and gl = 5
we find t(c) = 2.015
Now we calculate t (s) = ( x - μ₀ )/( σ/√n ) t(e) = -0.97/1.224
t(s) = - 0.79
The test is one tail test ( to the left) and t(s) = -0,79 is bigger than
t (c) = -1.64
So we are in the acceptance zone. We accept H₀
The expression 4a^2c^2 - (a^2-b^2+c^2)^2 has to be factored.
4a^2c^2 - (a^2 - b^2 + c^2)^2
=> (2ac)^2 - (a^2 - b^2 + c^2)^2
=> (2ac - a^2 + b^2 - c^2)(2ac + a^2 - b^2 + c^2)
=> (b^2 - (a^2 - 2ac + c^2))((a^2 + 2ac + c^2) - b^2)
=> (b^2 - (a - c)^2)((a + c)^2 - b^2)
=> (b - a + c)(b + a - c)(a + b + c)(a - b + c)
<span>
The factorized form of 4a^2c^2 - (a^2-b^2+c^2)^2 is (b - a + c)(b + a - c)(a + b + c)(a - b + c)</span>
This should be the answer
3.5 x 10^7
Answer:
d = 2750/Cos 48
Step-by-step explanation:
We need the value of the angle from the vertical axis
90 - 42 = 48°
We are trying to find the distance d which is the Hypotenuse of the right angled triangle formed.
The relationship between the adjacent and hypotenuse is help by the cosine of the angle between them
such that
Cos 48 = Adj/Hyp
Cos 48 = 2750/d
d Cos 48 = 2750
d = 2750/Cos 48
The machinist can produce 285 parts in 15 minutes. I know this because:
114 divided by 6 is 19. 19 multiplied by 15 is 285.