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bija089 [108]
3 years ago
9

I don’t know how to and i need answers pls

Mathematics
1 answer:
Assoli18 [71]3 years ago
5 0

Answer:

n

Step-by-step explanation:

maybe not for sure

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A number is selected from the set (1, 2, 3, 5, 15, 21, 29, 38, 500). If equal elemental probabilities are assigned, what is
Katen [24]

Answer:

\frac{7}{9} OR 77.78%

Step-by-step explanation:

So, we first need to find out how many numbers fit the "less than 29 or odd" group.

This would be: 1, 2, 3, 5, 15, 21, and 29, which is a total of 7 numbers.

Next, we figure out the total amount of numbers in the population.

This would be: 1, 2, 3, 5, 15, 21, 29, 38, and 500, which is a total of 9 numbers.

Finally, we put the first number (7) over the total (9) = \frac{7}{9}

\frac{7}{9} is now able to be written in a percentage, if you need.

The probability is \frac{7}{9} OR 77.78%

5 0
3 years ago
PLZ HELPP expand and simplify by collecting like terms <br> -2(4x+2y)(2x-y)
svet-max [94.6K]

Answer:

-4( 4x^2 -y^2)

Step-by-step explanation:

so I did the step on the paper

first line : is the equation itself

2nd line : I multiple the term in the parentheses together

3rd line: I multiple the - 2 to the term I got

4th line : I simplify it

6 0
3 years ago
Read 2 more answers
Which expressions are equal to 0 when x=-1? Check all that apply.
Reptile [31]

Answer:

4(x+1)/(4x+5)

4(x+1)/(5-4x)​

4(x-(-1))/(4x+5)

Step-by-step explanation:

The numerators in the fractions must equal to 0, or else the expressions won’t have the result of 0.

4(x+1)

4(-1+1)

4(0)

= 0

4(x-(-1))

4(-1-(-1))

4(-1+1)

4(0)

= 0

The expressions with the numerator as 0 have the result of 0.

7 0
3 years ago
If
baherus [9]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = \frac{\sqrt3}{2}

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}

Proof LHS → RHS:

LHS                          cos 165

Double-Angle:        cos (2 · 165) = 2 cos² 165 - 1

                             ⇒ cos 330 = 2 cos² 165 - 1

                             ⇒ 2 cos² 165  = cos 330 + 1

Given:                        2 \cos^2 165  = \dfrac{\sqrt3}{2} + 1

                              \rightarrow 2 \cos^2 165  = \dfrac{\sqrt3}{2} + \dfrac{2}{2}

Divide by 2:               \cos^2 165  = \dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \dfrac{2\sqrt3+4}{8}

Square root:             \sqrt{\cos^2 165}  = \sqrt{\dfrac{4+2\sqrt3}{8}}

Scratchwork:            \cos^2 165  = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2

                             \rightarrow \cos 165  = \pm \dfrac{\sqrt3+1}{2\sqrt2}

             Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

                             \rightarrow \cos 165  = - \dfrac{\sqrt3+1}{2\sqrt2}

LHS = RHS \checkmark

4 0
3 years ago
Select the correct answer.
eduard

If 30 is half price, then what is full price?

You can set up this problem like this:

30 = x/2

OR

30 = (1/2)x

where x is the full price.

To solve, simply multiply each half by 2:

2(30) = 2((1/2)x)

<u>x = $60</u>

4 0
2 years ago
Read 2 more answers
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