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mote1985 [20]
3 years ago
10

What is the y-intercept of y=-2x+6

Mathematics
2 answers:
Zanzabum3 years ago
8 0

Answer:

The y-intercept is (0,6)

Fiesta28 [93]3 years ago
6 0

The y-intercept is 6.

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Write an addition equation with a positive addend and negative addend and a resulting sum of -8
Ierofanga [76]
-18 + 10 = -8

------------------------------------
7 0
3 years ago
A random sample of size n1= 25, taken from a normal population with a standard deviation σ1= 5, has a mean X1= 80. A second rand
sesenic [268]

Answer:

The 94% confidence interval would be given by 2.898 \leq \mu_1 -\mu_2 \leq 7.102

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =80 represent the sample mean 1

\bar X_2 =75 represent the sample mean 2

n1=25 represent the sample 1 size  

n2=36 represent the sample 2 size  

\sigma_1 =5 sample standard deviation for sample 1

\sigma_2 =3 sample standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:

\bar X_1 -\bar X_2 =80-75=5

Since the Confidence is 0.94 or 94%, the value of \alpha=0.06 and \alpha/2 =0.03, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.03,0,1)".And we see that z_{\alpha/2}=1.88  

The standard error is given by the following formula:

SE=\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}

And replacing we have:

SE=\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=1.118

Confidence interval

Now we have everything in order to replace into formula (1):  

5-1.88\sqrt{\frac{5^2}{25}+\frac{3^2}{36}}=2.898  

5+1.8\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=7.102  

So on this case the 94% confidence interval would be given by 2.898 \leq \mu_1 -\mu_2 \leq 7.102  

7 0
3 years ago
Bobby put 1/3 of his lawn mowing money into his savings and uses the remaining 2/5 to buy a video game. If he has $12 left, how
Alexeev081 [22]

Given:

Bobby put 1/3 of his lawn mowing money into his savings

He uses the remaining 2/5 to buy a video game.

He has $12 left.

To find:

The amount did he have at first.

Solution:

Let x be the initial amount.

Bobby put 1/3 of his lawn mowing money into his savings. So, the remaining amount is

x-\dfrac{1}{3}x=\dfrac{2}{3}x

He uses the remaining 2/5 to buy a video game. Then the remaining amount is

Remaining=\dfrac{2}{3}x-\dfrac{2}{3}x\times \dfrac{2}{5}

Remaining=\dfrac{2}{3}x-\dfrac{4}{15}x

Remaining=\dfrac{10x-4x}{15}

Remaining=\dfrac{6x}{15}

Remaining=\dfrac{2x}{5}

It is given that the remaining amount is $12.

12=\dfrac{2x}{5}

12\times 5=2x

60=2x

Divide both sides by 2.

\dfrac{60}{2}=x

30=x

Therefore, Bobby have $30 at first.

6 0
3 years ago
SUPER EASY just need a percentage. WILL GIVE BRAINLY
schepotkina [342]
EL ESPANOL DU NARDE ES SI YAS MIASDAS
7 0
3 years ago
⚠️⚠️⚠️⚠️help⚠️⚠️⚠️⚠️​
Zigmanuir [339]
I say it’s 2/3 I mean that line means it’s a negative but there’s no negative 2 attached to the line
3 0
3 years ago
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