Answer:
sec²(x) - sec(x) + tan²(x) = (sec(x) - 1)(2sec(x) + 1)
Step-by-step explanation:
sec²(x) - sec(x) + tan²(x) =
= sec²(x) - sec(x) + [sec²(x) - 1]
= sec²(x) - sec(x) + [(sec(x) + 1)(sec(x) - 1)]
= sec(x)[sec(x) - 1] + [(sec(x) + 1)(sec(x) - 1)]
= (sec(x) - 1)(sec(x) + sec(x) + 1)
= (sec(x) - 1)(2sec(x) + 1)
Answer:
YOUR MOM
Step-by-step explanation:
LOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLOLO)LOLOLOLOLLOllll
The answer is the first option, <-20, -42>.
We can find this by first finding what -2u would equal by multiplying <5, 6> by -2. This gives us <-10, -12>.
Then we need to find out what 5v is equal to, by multiplying <-2, -6> by 5 to get <-10, -30>.
Now that we know what -2u and 5v are, we can substitute them into the equation and get
<-10, -12> + <-10, -30>, which we can split up into -10 - 10 = -20, and -12 - 30 = -42, so your final answer is <-20, -42>.
I hope this helps!
1 month = 17 536
6 months = 17 536 x 6
6 months = 105 216
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Ans: 105 216 miles
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X^4 - 4x^3 - 9x^2 + 36x = 0
x(x^3 - 4x^2 - 9x + 36) = 0
x(x^2(x - 4) - 9(x - 4) = 0
x(x + 3)(x - 3)(x - 4) = 0
the zeroes are -3, 0, 3, 4 Answer
