All categories

3 years ago

( I WILL BE GIVING EXTRA POINTS AND BRAINLIEST TO WHO EVER HELPS ME!! :D)

Mathematics

2 answers:

KatRina [158]3 years ago

3 0

Answer:

B I think

Step-by-step explanation:

Eight eighths in one cup. Took that and multiplied that and added the single eighth. Six sixths in one cup. Took that and multiplied that and added the single sixth again. Added the total up and got 10.2916666667. Rounded. Hope this helps!

N76 [4]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

p is inversely proportional to 3q-1. The difference in the values of p when q = 1 and q=2 respectively is 3. Find the value of p

Vsevolod [243]

Step-by-step explanation:

3q - 1 = 3(1) - 1 = 2

3q -1 = 3(2)- 1= 5

10/p = 2 10/p = 5

p= 5 p= 2 (5-2=3, so 10/p is correct)

q=5, 3(5) -1 = 14

10/p = 14

p = 0.71??

3 0

3 years ago

Good Night Bewtiful peeps!<br><br> What is 2097÷4?

Tom [10]

Answer: 2097÷4 = 524.25

4 0

3 years ago

Read 2 more answers

An angle is drawn in standard position passing through the unit circle at (0.643,0.766). The angle in standard position θ has a

Flura [38]

<h2>Hello!</h2>

The asnwer is: Cos50° ≈ 0.643

A unit circle is a cirgle with a radius equal of 1, knowing that, also know the following:

The angle is drawn passing trough the unit circle at (0.643,0.766) it means that:

$x=0.643\\y=0.766$

So,

Cos50° ≈ 0.643

We can prove that by following the next steps:

- If it's a unit circle,here is a right triangle with hypotenuse of 1,

$1^{2}=x^{2}+y^{2}$

$1^{2}=0.643^{2}+0.766^{2}$

$1^{2}=0.4134 +0.5867$

$1=1.0001=1$

- We can determine the cosine of the angle by the following formula:

$cos(\alpha)=\frac{x}{hypotenuse} \\cos(\alpha)^{-1}=cos(\frac{0.643}{1})^{-1} \\\alpha=49.98$

Therefore,

Cos(α)=49.98°≈50°

Also, if there is a right triangle, according to the Pythagorean Thorem:

$1^{2}=(Cos(\alpha))^{2}+(Sin(\alpha))^{2} \\Cos(50)=\sqrt{1-(Sin(50))^{2}}=0.6427$

Hence,

Cos50° ≈ 0.643

Have a nice day!

3 0

3 years ago

Read 2 more answers

I think it’s b but I may be wrong

leonid [27]

Answer:

D, not B

Step-by-step explanation:

So using Pythagorean Theorem:

$C^{2} =A^{2} +B^{2} \\x^{2} =144+265\\x^{2} =400\\x=20$

Yep, It's not B, But D.

Hope this helps!

Stay Safe!

6 0

3 years ago

Write a cosine function that has an amplitude of 2, a midline of 5 and a period of \frac{3\pi}{4} 4 3π .

kakasveta [241]

Given:

Amplitude = 2

Midline = 5

Period of $\dfrac{3\pi}{4}$ .

To find:

The cosine function.

Solution:

The general cosine function is:

$f(x)=A\cos(Bx+C)+D$ ...(i)

Where, |A| is amplitude, $\dfrac{2\pi}{B}$ is period, $-\dfrac{C}{B}$ is phase shift and D is the mid line.

Period of function is $\dfrac{3\pi}{4}$ . So,

$\dfrac{3\pi}{4}=\dfrac{2\pi}{B}$

$B=2\pi\times \dfrac{4}{3\pi}$

$B=\dfrac{8}{3}$

Substituting $A=2,\ B=\dfrac{8}{3},\ C=0,\ D=5$ in (i), we get

$f(x)=2\cos(\dfrac{8}{3}x+0)+5$

$f(x)=2\cos(\dfrac{8}{3}x)+5$

Therefore, the required cosine function is $f(x)=2\cos(\dfrac{8}{3}x)+5$ .

6 0

3 years ago