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3 years ago

( I WILL BE GIVING EXTRA POINTS AND BRAINLIEST TO WHO EVER HELPS ME!! :D)

Mathematics

2 answers:

KatRina [158]3 years ago

3 0

Answer:

B I think

Step-by-step explanation:

Eight eighths in one cup. Took that and multiplied that and added the single eighth. Six sixths in one cup. Took that and multiplied that and added the single sixth again. Added the total up and got 10.2916666667. Rounded. Hope this helps!

N76 [4]3 years ago

3 0

Answer:

Step-by-step explanation:

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Write an addition sentence that helps you solve 51 - 9

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Answer:

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3 years ago

Any 10th grader solve it for 50 points

kkurt [141]

Answer:

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0$ is proved for the sum of pth, qth and rth terms of an arithmetic progression are a, b,and c respectively.

Step-by-step explanation:

Given that the sum of pth, qth and rth terms of an arithmetic progression are a, b and c respectively.

First term of given arithmetic progression is A

and common difference is D

ie., $a_{1}=A$ and common difference=D

The nth term can be written as

$a_{n}=A+(n-1)D$

pth term of given arithmetic progression is a

$a_{p}=A+(p-1)D=a$

qth term of given arithmetic progression is b

$a_{q}=A+(q-1)D=b$ and

rth term of given arithmetic progression is c

$a_{r}=A+(r-1)D=c$

We have to prove that

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)=0$

Now to prove LHS=RHS

Now take LHS

$\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)$

$=\frac{A+(p-1)D}{p}\times (q-r)+\frac{A+(q-1)D}{q}\times (r-p)+\frac{A+(r-1)D}{r}\times (p-q)$

$=\frac{A+pD-D}{p}\times (q-r)+\frac{A+qD-D}{q}\times (r-p)+\frac{A+rD-D}{r}\times (p-q)$

$=\frac{Aq+pqD-Dq-Ar-prD+rD}{p}+\frac{Ar+rqD-Dr-Ap-pqD+pD}{q}+\frac{Ap+prD-Dp-Aq-qrD+qD}{r}$

$=\frac{[Aq+pqD-Dq-Ar-prD+rD]\times qr+[Ar+rqD-Dr-Ap-pqD+pD]\times pr+[Ap+prD-Dp-Aq-qrD+qD]\times pq}{pqr}$

$=\frac{Arq^{2}+pq^{2} rD-Dq^{2} r-Aqr^{2}-pqr^{2} D+qr^{2} D+Apr^{2}+pr^{2} qD-pDr^{2} -Ap^{2}r-p^{2} rqD+p^{2} rD+Ap^{2} q+p^{2} qrD-Dp^{2} q-Aq^{2} p-q^{2} prD+q^{2}pD}{pqr}$

$=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2}-pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}$

$=\frac{Arq^{2}-Dq^{2}r-Aqr^{2}+qr^{2}D+Apr^{2} -pDr^{2}-Ap^{2}r+p^{2}rD+Ap^{2}q-Dp^{2}q-Aq^{2}p+q^{2}pD}{pqr}$

$\neq 0$

ie., $RHS\neq 0$

Therefore $LHS\neq RHS$

ie., $\frac{a}{p}\times (q-r)+\frac{b}{q}\times (r-p)+\frac{c}{r}\times (p-q)\neq 0$

Hence proved

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3 years ago

Three cubes of the same metal, whose edges are 6, 8, 10 cm are meltedand formed into a single cube. Find the diagonal of the sin

allochka39001 [22]

Answer: 12√2 cm

Step-by-step explanation:

Cube 1: V = 6³ = 216

Cube 2: V = 8³ = 512

Cube 3: V = 10³ = 1000

New Cube: V = 1728

1728 = s³

12 = s

So, each side of the new cube is 12 cm.

Use Pythagorean Theorem to find the length of the diagonal:

12² + 12² = diagonal²

144 + 144 = diagonal²

288 = diagonal²

√288 = diagonal

12√2 = diagonal

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3 years ago

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Butoxors [25]

Answer:

Well you can already answer that(37)

Step-by-step explanation:

In 3 hours and 30 minutes Greg has earned 64.75 dollars if you take that amount(the amount earned in 3 and a half hours) and divide it by the 3 1/2 hours(the time it took to earn that amount) you get 18.50 which is the amount you earn per half hour since that graph is increasing at 30min. per 18.50 or the amount.

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4 years ago