3 years ago

Can someone help me solve this problem (graphing/geometry)

1 answer:

5 0

Answer:

Step-by-step explanation:

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uysha [10]

Answer:

The value of k that makes the relationship shown in the table below proportional is $\mathbf{\frac{1}{2}}$

Step-by-step explanation:

The relation is proportional if $y=kx \:or\:k=\frac{y}{x}$

Putting values of x and y to find k.

For x =2 and y =1 k is: $k=\frac{y}{x}=\frac{1}{2}$

For x =4 and y =2 k is: $k=\frac{y}{x}=\frac{2}{4} =\frac{1}{2}$

For x =6 and y = 3 k is: $k=\frac{y}{x}=\frac{3}{6} =\frac{1}{2}$

For x = 8 and y = 4 k is: $k=\frac{y}{x}=\frac{4}{8} =\frac{1}{2}$

For x =10 and y = 5 k is: $k=\frac{y}{x}=\frac{5}{10} =\frac{1}{2}$

So, The value of k that makes the relationship shown in the table below proportional is $\mathbf{\frac{1}{2}}$

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Tema [17]

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pentagon [3]

I'm going to guess B but I'm not sure

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Step-by-step explanation:

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