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Anna71 [15]
3 years ago
5

Can someone help me solve this problem (graphing/geometry)

Mathematics
1 answer:
PIT_PIT [208]3 years ago
5 0

Answer:

24

Step-by-step explanation:

i quessed

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Which correctly describes how the graph of the inequality −4y − x ≥ 7 is shaded?
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Answer: Below the solid line

Step-by-step explanation:

-4y - x ≥ 7

add x to both sides

-4y ≥ x + 7

divide by -4 on both sides

y ≤ -1/4x - 7/4 = (1.75)

Take the origin (0,0) and substitute it for the variables

y(0) ≤ -1/4(0) - 7/4

0 ≤ -7/4 = (1.75)

This statement is false, so you would shade on a graph, below the solid line, since this is where the origin would not be.

The line would be solid because the < is underlined.

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5x88x9x7x3x9x10x31x47=
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Find the volume of the prism.
ExtremeBDS [4]

Answer:

Its A.

Step-by-step explanation:

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In the situation, simple interest is calculated yearly. How much interest was earned?
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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
Lapatulllka [165]

Answer:

Step-by-step explanation:

Given that there is a function of x,

f(x) = 2sin x + 2cos x,0\leq x\leq 2\pi

Let us find first and second derivative for f(x)

f'(x) = 2cosx -2sinx\\f"(x) = -2sinx-2cosx

When f'(x) =0 we have tanx = 1 and hence

a) f'(x) >0 for I and III quadrant

Hence increasing in (0, \pi/2) U(\pi,3\pi/2)\\

and decreasing in (\pi/2, \pi)U(3\pi/2,2\pi)

x=\frac{\pi}{4}, \frac{3\pi}{4}

f"(\pi/4)

Hence f has a maxima at x = pi/4 and minima at x = 3pi/4

b) Maximum value = 2sin \pi/4+2cos \pi/4 =2\sqrt{2}

Minimum value = 2sin 3\pi/4+2cos 3\pi/4 =-2\sqrt{2}

c)

f"(x) =0 gives tanx =-1

x= 3\pi/4, 7\pi/4

are points of inflection.

concave up in (3pi/4,7pi/4)

and concave down in (0,3pi/4)U(7pi/4,2pi)

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