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Oksi-84 [34.3K]
4 years ago
10

8x5x2x4 whats dis answer

Mathematics
1 answer:
scoray [572]4 years ago
5 0

Answer:

320

Step-by-step explanation:

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Another scale drawing of Jimmy's living room is shown below:
deff fn [24]

Answer:

last option

Step-by-step explanation:

Again, 1 cm represents 8 / 2 = 4 feet so the width is 4 * 4 = 16 and the length is 6 * 4 = 24.

5 0
3 years ago
​
DedPeter [7]

Answer:

The solution is (3/8, -7/8).

Step-by-step explanation:

y = −5x + 1

y = 3x − 2

Since  the 2 expressions in x are both equal to y :

−5x + 1  = 3x - 2

-5x - 3x = -2 - 1

-8x = -3

x = 3/8.

So y = 3x - 2

= 3(3/8) - 2

= 9/8 - 2 = -7/8.

6 0
3 years ago
If a/b=5/3 then 3a = ____.
Tresset [83]
Answer: 15
a=5, b=3
3a= 3x5= 15
3 0
3 years ago
Read 2 more answers
Use implicit differentiation to find the points where the parabola defined by x2−2xy+y2+4x−8y+20=0 has horizontal and vertical t
Komok [63]

Answer:

The parabola has a horizontal tangent line at the point (2,4)

The parabola has a vertical tangent line at the point (1,5)

Step-by-step explanation:

Ir order to perform the implicit differentiation, you have to differentiate with respect to x. Then, you have to use the conditions for horizontal and vertical tangent lines.

-To obtain horizontal tangent lines, the condition is:

\frac{dy}{dx}=0 (The slope is zero)

--To obtain vertical tangent lines, the condition is:

\frac{dy}{dx}=\frac{1}{0} (The slope is undefined, therefore the denominator is set to zero)

Derivating respect to x:

\frac{d(x^{2}-2xy+y^{2}+4x-8y+20)}{dx} = \frac{d(x^{2})}{dx}-2\frac{d(xy)}{dx}+\frac{d(y^{2})}{dx}+4\frac{dx}{dx}-8\frac{dy}{dx}+\frac{d(20)}{dx}=2x -2(y+x\frac{dy}{dx})+2y\frac{dy}{dx}+4-8\frac{dy}{dx}= 0

Solving for dy/dx:

\frac{dy}{dx}(-2x+2y-8)=-2x+2y-4\\\frac{dy}{dx}=\frac{2y-2x-4}{2y-2x-8}

Applying the first conditon (slope is zero)

\frac{2y-2x-4}{2y-2x-8}=0\\2y-2x-4=0

Solving for y (Adding 2x+4, dividing by 2)

y=x+2 (I)

Replacing (I) in the given equation:

x^{2}-2x(x+2)+(x+2)^{2}+4x-8(x+2)+20=0\\x^{2}-2x^{2}-4x+x^{2} +4x+4+4x-8x-16+20=0\\-4x+8=0\\x=2

Replacing it in (I)

y=(2)+2

y=4

Therefore, the parabola has a horizontal tangent line at the point (2,4)

Applying the second condition (slope is undefined where denominator is zero)

2y-2x-8=0

Adding 2x+8 both sides and dividing by 2:

y=x+4(II)

Replacing (II) in the given equation:

x^{2}-2x(x+4)+(x+4)^{2}+4x-8(x+4)+20=0\\x^{2}-2x^{2}-8x+x^{2}+8x+16+4x-8x-32+20=0\\-4x+4=0\\x=1

Replacing it in (II)

y=1+4

y=5

The parabola has vertical tangent lines at the point (1,5)

4 0
3 years ago
We want to compare the quality of three Tablet products: Tablet Product A has a Mean Time Between Failures (MTBF) 10,000 hours,
skelet666 [1.2K]

Answer:

The Availability of tablets A,B and C are equal

Step-by-step explanation:

Computation for Which tablet has better Availability

Using this formula

Availability of Tablet=MTBF/ ( MTBF + MTTR)

Where,

MTBF represent Mean Time Between Failures

MTTR represent Mean Time To Repair

Let plug in the formula

Availability of Tablet A = 10,000hrs/(10,000hrs + 10hrs)

Availability of Tablet A= 0.999

Availability of tablet B = 11,000hrs/( 11,000hrs + 11hrs )

Availability of Tablet B= 0.999

Availability of Tablet C = 12,000hrs/ ( 12,000hrs + 12hrs)

Availability of Tablet C= 0.999

Based on the above calculation the Availability of all the 3 tablets are equal

Therefore the Availability of tablets A,B and C are equal.

3 0
3 years ago
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