Question

Find the area of △ABC with side lengths b = 6 and c = 17, and included angle A = 135∘. Round your answer to the nearest tenth.

Answer 1

Answer:

$A=36.1\ units^2$

Step-by-step explanation:

we know that

The area of a triangle applying the law of sines is given by the formula

$A=\frac{1}{2}(b)(c)sin(A)$

where

A is the included angle between the sides b and c

substitute the given values

$A=\frac{1}{2}(6)(17)sin(135^o)=36.1\ units^2$