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pshichka [43]
2 years ago
15

You saved $20 per week to purchase one of three bikes in the store near your home. The starting price for the bikes is $130.

Mathematics
2 answers:
Nadusha1986 [10]2 years ago
8 0

Answer:

6.5 weeks without parental help, 3.5 weeks with help from your parents.

Step-by-step explanation:

The Equation is:

Y = 20x

Y = Starting price for bikes

X = # of weeks

Therefore:

$130 = 20x

This can be simplified by solving for x

x = 130/20

x = 6.5 weeks

If your parents gave you $60 to help buy the bike the equation would be written as:

Y = 20x + 60

$130 = 20x + 60

Subtract 60 from both sides to get:

$70 = 20x

Solve for x

x = 70/20

x = 3.5 weeks

Neporo4naja [7]2 years ago
6 0

Answer:

4 weeks

Step-by-step explanation:

basic math

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Answer:

938350 \\

Step-by-step explanation:

938600 - 250 = 938350

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2 years ago
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What is the solution of RootIndex 3 StartRoot x + 8 EndRoot = negative 4?
erica [24]

Answer: First option.

Step-by-step explanation:

Given the following equation provided in the exercise:

\sqrt[3]{x+8}=-4

You can follow the steps indicated below in order to find the solution of this equation:

1. Cubing both sides of the equation, you get:

(\sqrt[3]{x+8})^3=(-4)^3\\\\x+8=-64

2. Finally you must subtract 8 from both sides of the equation:

x+8-8=-64-8\\\\x=-72

You can notice that this solution matches with the first option.

5 0
3 years ago
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Can y = sin(t2) be a solution on an interval containing t = 0 of an equation y + p(t) y + q(t) y = 0 with continuous coefficient
JulsSmile [24]

Answer:

Step-by-step explanation:

y = sin(t^2)

y' = 2tcos(t^2)

y'' = 2cos(t^2) - 4t^2sin(t^2)

so the equation become

2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0

when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.

7 0
3 years ago
solve x^2-8x=20 by completing the square. Which is the solution set of the equation? a {2, 10} b {-2, 10} c {2, -10} d {-2, -10}
torisob [31]

Answer:

B is the correct answer.

Step-by-step explanation:

7 0
3 years ago
part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.​
Nat2105 [25]

Answer:  \bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}

<u>Step-by-step explanation:</u>

Pythagorean Theorem is: a² + b² = c²   , <em>where "c" is the hypotenuse</em>

<em />

9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}

Note: 4² + (8√2)² = hypotenuse²   →   hypotenuse = 12

10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}

Note: 12² + opposite² = 20²   →   opposite = 16

11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}

Note: adjacent² + 5² = 6²   →   adjacent = √11

12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}

Note: adjacent² + 7² = (13√2)²   →   adjacent = 17

5 0
3 years ago
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