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arlik [135]
3 years ago
11

Ramp 10 feet high and 32 long

Mathematics
2 answers:
madam [21]3 years ago
8 0

A. IMA = 32/10 = 3.2

harkovskaia [24]3 years ago
8 0

we would solve this by using the equation: LMA=L/H

now, we have to plug in the numbers LMA= 32/10

LMA= 3.2

so, the answer is 3.2

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PLEASE I AM IN DESPERATE NEED OF HELP
erastova [34]

Answer:

C:   H <u>> </u> 60

Step-by-step explanation:

H is 60 in or taller, underlined indicates that it's also 60 in, not just above it.

8 0
2 years ago
The diagram below , not drawn to scale , shows three points R , S and F on the horizontal
Katyanochek1 [597]

The question is an illustration of right-angled triangles.

  • <em>The length of RF is 49.1 m</em>
  • <em>The length of SR is 65.5 m</em>
  • <em>The elevation from S to T is 30 degrees</em>

See attachment for the sketch

<u>(a) Show that RF = 49.1</u>

Considering \triangle FTR

We have:

\tan(R) = \frac{FT}{RF} ---- tangent ratio

This gives:

\tan(27) = \frac{25}{RF}

Make RF the subject

RF = \frac{25}{\tan(27)}

RF = 49.06

Approximate

RF = 49.1

<u>(b) Calculate SR</u>

Considering \triangle FRS

We have:

SR^2 = RF^2 + FS^2 ---- Pythagoras theorem

This gives

SR^2 = 49.1^2 + 43.3^2

SR^2 = 4285.7

Take square roots

SR = 65.5

<u>(c) The elevation from S to T</u>

To do this, we make use of tangent ratio from \triangle FST

\tan(S) = \frac{FT}{FS}

\tan(S) = \frac{25}{43.3}

Take arc tan of both sides

S = \tan^{-1}(\frac{25}{43.3})

S = 30^o

Read more about right-angled triangles at:

brainly.com/question/3770177

8 0
3 years ago
Find f(5) for this sequence:
alexira [117]
Answer is

2+4+4=10

f(5)=10
5 0
4 years ago
Perform the indicated operation (x^2-2x+4)(3-x)^2
olga2289 [7]
<span>(x^2-2x+4)(3-x)^2 that should be the right answer</span>
4 0
3 years ago
An object is dropped from the top of Pittsburgh's USX Towers, which is 841 feet tall. The
dlinn [17]

Answer:

Step-by-step explanation:

h(t) = 841 - 16t

[Is this written correctly?  The time is usually t^2, not t.  I'll solve with the written equation, but check the equation]

The height at ground level is 0, so we want the value of t when h(t) = 0:

0 = 841 - 16t

-16t = -841

t = 53 seconds

One can also graph this formula and find the time to hit the ground at the point the line intersects the x axis (x = 0).

====

If the equation should have read h(t) = 841 - 16t^2, solve it as above, setting h(t) = 0.

t = (29/4) seconds

This can also be graphed.

8 0
3 years ago
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