Answer:
The rate of change of the tracking angle is 0.05599 rad/sec
Step-by-step explanation:
Here the ship is traveling at 15 mi/hr north east and
Port to Radar station = 2 miles
Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles
Therefore the ship, port and radar makes a triangle with sides
2, 7.5 and x
The value of x is gotten from cosine rule as follows
x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04
x = 6.25 miles
By sine rule we have
Therefore,
α = Angle between radar and ship α
∴ α = 58.052
Where we put
to get
and differentiate to get
= 3.208 degrees/second = 0.05599 rad/sec.
$2.16 per 0.9 pounds of granola
Answer:
14.3 km
Step-by-step explanation:
Using the paths shown, we would need to add the path length from Belmont to Yardley and Yardley to Oxford. When we add 8.5 and 5.8, we get 14.3 km.
Hence,
the distance from Belmont to Oxford is 14.3 km.
Hope this helps!!! PLZ MARK BRAINLIEST!!!
By the laws of logs
log p/n = log p - log n = 6
log m/n = log m - log n = 8 subtract
log m - log p = 2
log m/p = 2
So m / p = 100
Answer:
It’s B. (y=√x-5 - 10)
Step-by-step explanation:
I used a math app soooo yeah— hope this helps ya’ll.
