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1 year ago

Which numbers below are part of the domain for this graph? Select all that apply.

Mathematics

1 answer:

olya-2409 [2.1K]1 year ago

6 0

The numbers which are a part of the domain for the graph are: 6, 1 and 2.

<h3>Which numbers are part of the domain?</h3>

The domain of a graph is a set of all possible input, x-values. Consequently, since the domain of the graph given ranges over intergers, 1 to 10, it follows that numbers which are part of the domain are; 6, 2, and 1.

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Find the number, if d 12/13 of it is 24

Inessa [10]

Answer:

26 is the number

Step-by-step explanation:

12/13 x = 24

Multiply by 13 on both sides

12x = 24 * 13

12x = 312

Simplify

x = 26

Hope this helps :)

5 0

3 years ago

Item 14

dsp73

Answer:

13/21

Step-by-step explanation:

5 0

2 years ago

Which of the following are solutions to the equation below?

sladkih [1.3K]

Answer:

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

Step-by-step explanation:

considering the equation

$2x^2\:-\:4x\:-\:3\:=\:x$

solving

$2x^2\:-\:4x\:-\:3\:=\:x$

$2x^2-4x-3-x=x-x$

$2x^2-5x-3=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

solving

$x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5+\sqrt{49}}{2\cdot \:2}$

$x=\frac{5+7}{4}$

$x=3$

also solving

$x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5-\sqrt{49}}{4}$

$x=-\frac{2}{4}$

$x=-\frac{1}{2}$

Therefore,

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

7 0

3 years ago

Which fraction is equivalent to ?<br><br> 7/10 cup<br> 7/9 cup<br> 7/7 cup<br> 7/1 cup

polet [3.4K]

14/20
14/18
1
7
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3 0

3 years ago

As voters exit the polls, you ask a representative random sample of voters if they voted for a proposition. If the true percenta

tresset_1 [31]

Answer:

The probability is 0.057797

Step-by-step explanation:

Consider the provided information.

It is given that true percentage of voters who vote for the proposition is 63%,

Let p is probability of success.

According to the binomial distribution:

$P(x;p,n)=^nC_x(p)^x(1-p)^{(n-x)}$

Substitute n=7, p=0.63 and x=2 in the above formula.

$P(x;p,n)=^7C_2(0.63)^2(1-0.63)^{(7-2)}$

$P(x;p,n)=\frac{7!}{2!5!}(0.3969)(0.37)^{5}\\P(x;p,n)=21(0.3969)(0.37)^{5}\\P(x;p,n)=0.0577974947199\\P(x;p,n)\approx0.057797$

Hence, the probability is 0.057797

8 0

3 years ago