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3 years ago

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On New Years’s Eve, the temperate fell by 24 degrees in a span of 6 hours. By how many degrees did the temperature fall every ho

ur?

1 answer:

Novosadov [1.4K]3 years ago

7 0

The temperature fell by 24 degrees in 6 hours. We need to find out how many degrees did the temperature fall every hour.

You can <u>divide</u> 24 with 6.

24 ÷ 6 = 4

Your answer is 4

hope this helps!

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Three fourths of a class brought bundles of old papers to school. If 40 students were in class, how many students brought papers

Vaselesa [24]

Answer:

300 students

Step-by-step explanation:

Hope this answer helps you :)

Have a great day

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3 years ago

Suppose that each time Giannis Antetokounmpo shoots a free throw, he has a 3/4 probability of success. If Giannis shoots three f

GREYUIT [131]

Answer:

84.38% probability that he succeeds on at least two of them

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either Giannis makes it, or he does not. The free throws are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

He has a 3/4 probability of success.

This means that $p = \frac{3}{4} = 0.75$

Giannis shoots three free throws

This means that $n = 3$

What is the probability that he succeeds on at least two of them

$P(X \geq 2) = P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{3,2}.(0.75)^{2}.(0.25)^{1} = 0.4219$

$P(X = 3) = C_{3,3}.(0.75)^{3}.(0.25)^{0} = 0.4219$

$P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4219 + 0.4219 = 0.8438$

84.38% probability that he succeeds on at least two of them

6 0

2 years ago

Consider H0: μ = 45 versus H1: μ < 45. A random sample of 25 observations produced a sample mean of 41.8. Using α = .025 and

a_sh-v [17]

Given
$H0: \ \mu=45 \\ \\ H1: \ \mu\ \textless \ 45$
This is a one-tailed test.

$z= \frac{41.8-45}{6/ \sqrt{25} } = \frac{-3.2}{6/5} = \frac{-3.2}{1.2} =-2.6667$

$P(z\ \textless \ -2.6667)=0.00383$

Since the p-value of the sample statistic (0.00383) is less that the significant level (0.025), we reject the null hypothesis.

5 0

3 years ago

What is the value of the expression 9 x 4 - (2 x 1/2)

love history [14]

Answer:

35x

Step-by-step explanation:

Start with parentheses, 2 x 1/2 = 1

9 x 4 = 36

36 - 1 = 35

4 0

3 years ago

Express sin A,cos A and tan A as ratios

OverLord2011 [107]

Answer:

Part A) $sin(A)=\frac{2\sqrt{42}}{23}$

Part B) $cos(A)=\frac{19}{23}$

Part C) $tan(A)=\frac{2\sqrt{42}}{19}$

Step-by-step explanation:

Part A) we know that

In the right triangle ABC of the figure the sine of angle A is equal to divide the opposite side angle A by the hypotenuse

so

$sin(A)=\frac{BC}{AB}$

substitute the values

$sin(A)=\frac{2\sqrt{42}}{23}$

Part B) we know that

In the right triangle ABC of the figure the cosine of angle A is equal to divide the adjacent side angle A by the hypotenuse

so

$cos(A)=\frac{AC}{AB}$

substitute the values

$cos(A)=\frac{19}{23}$

Part C) we know that

In the right triangle ABC of the figure the tangent of angle A is equal to divide the opposite side angle A by the adjacent side angle A

so

$tan(A)=\frac{BC}{AC}$

substitute the values

$tan(A)=\frac{2\sqrt{42}}{19}$

8 0

2 years ago