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Maru [420]
3 years ago
13

Please help. I need help on how to explain this. The answer is 22 times but I just don’t know how to explain how to get the answ

er.

Mathematics
1 answer:
AlladinOne [14]3 years ago
6 0
I know the best prediction to find out how much times it will land on earbuds. My prediction is that it will land on earbuds twenty-two time.
Can you mark me brainliest?
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12 to 15<br> Help Gracias
Ray Of Light [21]

Answer: 13, 14

Step-by-step explanation:

I counted

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3 years ago
Compare the fractions. −67 −17
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-17 is fifty more positive than -67 (hope this  help)
7 0
3 years ago
The following is a special trapezoid. Given WX is parallel to ZY. Which of the following is also true about trapezoid WXYZ?
Lena [83]

Answer:

∠Z and ∠W are supplementary

Step-by-step explanation:

In the diagram given showing a special trapezoid, WX and ZY are two opposite sides that are parallel to each other.

Thus, consecutive angles would be supplementary.

Therefore, the only correct option that is true is:

∠Z and ∠W are supplementary.

The test options are incorrect as consecutive angles are not complementary and they are not in themselves congruent to each other.

7 0
3 years ago
Cross multiply the numbers
love history [14]

Answer:

2m/4m = 9m/xm

2m(xm) = 4m(9m)

2xm = 36m

7 0
1 year ago
Lyles height is twice the difference of the height of his brother, harry, and the height of his dad, vince. Lyle is 2 1/2 feet t
Greeley [361]

Answer:

5 = 19 - 4v

Step-by-step explanation:

We are given the following in the question:

\text{Lyle's height} = 2( \text{Harry's height - Vince's height})

Let l be Lyle's height, h be Harry's height and v be Vince's height.

Thus, we can write:

l = 2(h-v)

Lyle's Height =

2\dfrac{1}{2}\text{ feet}

Harry's height =

4\dfrac{3}{4}\text{ feet}

Putting the value in the equation:

2\dfrac{1}{2} = 2(4\dfrac{3}{4}- v)\\\\\dfrac{5}{2} = \dfrac{19}{2} - 2v\\\\5 = 19 - 4v\\4v = 19-5\\\\v = \dfrac{14}{4}\\\\v = 3\dfrac{2}{4} = 3\dfrac{1}{2}

Thus, Vince's height is 3.5 feet.

7 0
4 years ago
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