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pantera1 [17]
1 year ago
15

Without actual calculating the cubes, evaluate using identities:

id="TexFormula1" title="-11^3+8^3+3^3" alt="-11^3+8^3+3^3" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
djyliett [7]1 year ago
5 0

Answer:

-792

Step-by-step explanation:

wariber [46]1 year ago
5 0

\huge\textsf{Hey there!}


\mathsf{-11^3 + 8^3 + 3^3}

\mathsf{= -11\times -11\times -11 + 8\times8\times8 + 3\times3\times3}

\mathsf{= 121\times -11+ 64\times8+9\times3}

\mathsf{= -1,331 + 512 + 27}

\mathsf{= -819 + 27}

\mathsf{= -792}


\huge\textsf{Therefore, your answer should be: \boxed{\mathsf{-792}}}\huge\checkmark


\huge\textsf{Good luck on your assignment \& enjoy your day!}


~\frak{Amphitrite1040:)}

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Step-by-step explanation:

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Let's start with the triangles.

1. To find the area of a triangle, the formula is  \frac{1}{2} b*h. It is given that the base of one triangle is equal to 1.1 in and the height is equal to 3.8 in., so in the equation, it would look like:

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2. So now that we know one triangle is equal to 2.09 in², we now know that the other triangle is equal to the same area. To find the total of the two triangles you need to multiply the area by 2:

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