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pantera1 [17]
2 years ago
15

Without actual calculating the cubes, evaluate using identities:

id="TexFormula1" title="-11^3+8^3+3^3" alt="-11^3+8^3+3^3" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
djyliett [7]2 years ago
5 0

Answer:

-792

Step-by-step explanation:

wariber [46]2 years ago
5 0

\huge\textsf{Hey there!}


\mathsf{-11^3 + 8^3 + 3^3}

\mathsf{= -11\times -11\times -11 + 8\times8\times8 + 3\times3\times3}

\mathsf{= 121\times -11+ 64\times8+9\times3}

\mathsf{= -1,331 + 512 + 27}

\mathsf{= -819 + 27}

\mathsf{= -792}


\huge\textsf{Therefore, your answer should be: \boxed{\mathsf{-792}}}\huge\checkmark


\huge\textsf{Good luck on your assignment \& enjoy your day!}


~\frak{Amphitrite1040:)}

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Answer:

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Step-by-step explanation:

<u>The speed is:</u>

  • 100 m in 9 seconds

<u>To find:</u>

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Distance = speed * time

<u>Distance is:</u>

  • 100/9  meter /seconds * 1 min and 2 seconds =
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Dee saves $20 a week for 10 weeks. during her 5-day vacation, she plans to spend $6.75 each day for snacks. which expression sho
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$20 a week for 10 weeks is:

20*10 = $200


She spends $6.75 each day for 5 days:

6.75*5 = $33.75.


Lets subtract her spending from her savings to find out how much she has left:

$200-$33.75 = $166.25

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The 11th term of an progression is 25 and the sum of the first 4 terms is 49. The nth term of the progression is 49
KIM [24]

<u>Answer:</u>

<u>For 1:</u> The first term is 10 and the common difference is \frac{3}{2}

<u>For 2:</u> The value of n is 27

<u>Step-by-step explanation:</u>

The n-th term of the progression is given as:

a_n=a_1+(n-1)d

where,

a_1 is the first term, n is the number of terms and d is the common difference

The sum of n-th terms of the progression is given as:

S_n=\frac{n}{2}[2a_1+(n-1)d]

where,

S_n is the sum of nth terms

  • <u>For (1):</u>

The 11th term of the progression:

25=a_1+10d               .......(1)

Sum of first 4 numbers:

49=\frac{4}{2}[2a_1+3d              ......(2)

Forming equations:

98=8a_1+12d

25=a_1+10d                  ( × 8)

The equations become:

98=8a_1+12d

200=8a_1+80d

Solving above equations, we get:

102=68d\\\\d=\frac{102}{68}=\frac{3}{2}

Putting value in equation (1):

25=a_1+10\frac{3}{2}\\\\a_1=[25-15]=10

Hence, the first term is 10 and the common difference is \frac{3}{2}

  • <u>For 2:</u>

The nth term is given as:

49=10+(n-1)\frac{3}{2}

Solving the above equation:

39=(n-1)\frac{3}{2}\\\\n-1=26\\\\n=27

Hence, the value of n is 27

3 0
3 years ago
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