x2=36
We move all terms to the left:
x2-(36)=0
We add all the numbers together, and all the variables
x^2-36=0
a = 1; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·1·(-36)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x1=−b−Δ√2ax2=−b+Δ√2a
Δ‾‾√=144‾‾‾‾√=12
x1=−b−Δ√2a=−(0)−122∗1=−122=−6
x2=−b+Δ√2a=−(0)+122∗1=122=6
5x=3x+20
5x-3x=3x-3x+20
2x=20
2x/2=20/2
X=10 Hope this helped!
-Twix
Answer:
Ok
Step-by-step explanation:
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Answer
The answer is 36.
Explanation:
Let the unknown number be x
x^3=x*36
or, x^3/x=36
or, x^2=36
or, x=6
.•. x=36