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pantera1 [17]
2 years ago
15

Without actual calculating the cubes, evaluate using identities:

id="TexFormula1" title="-11^3+8^3+3^3" alt="-11^3+8^3+3^3" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
djyliett [7]2 years ago
5 0

Answer:

-792

Step-by-step explanation:

wariber [46]2 years ago
5 0

\huge\textsf{Hey there!}


\mathsf{-11^3 + 8^3 + 3^3}

\mathsf{= -11\times -11\times -11 + 8\times8\times8 + 3\times3\times3}

\mathsf{= 121\times -11+ 64\times8+9\times3}

\mathsf{= -1,331 + 512 + 27}

\mathsf{= -819 + 27}

\mathsf{= -792}


\huge\textsf{Therefore, your answer should be: \boxed{\mathsf{-792}}}\huge\checkmark


\huge\textsf{Good luck on your assignment \& enjoy your day!}


~\frak{Amphitrite1040:)}

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\boxed{(6, -3)}

Step-by-step explanation:

Given the ratio 5:3

and Points A and B where A is located at (-6, 3), and B is located at (26, -13).

Let point A be (x_{1}, y_{1}), and let point B be (x_{2}, y_{2}).

(-6, 3) → (x_{1}, y_{1}).

(26, -13) → (x_{2}, y_{2}).

Let 5 be n, and 3 be m.

5:3 → n:m

(\frac{nx_{1} + mx_{2}}{n+m}, \frac{ny_{1} + my_{2}}{n + m}).

To solve, just substitute these variables into the expressions of these coordinates to get the answer.

(\frac{nx_{1} + mx_{2}}{n+m}, \frac{ny_{1} + my_{2}}{n + m}) →

(\frac{(5)x_{1} + (3)x_{2}}{(5)+(3)}, \frac{(5)y_{1} + (3)y_{2}}{(5) + (3)}) →

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→

(6, -3).

Thus the coordinates of B are:

\boxed{(6, -3)}

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3 years ago
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