Write a recursive rule for the sequence. 3, 8, 13, 18, 23, ...

Mathematics

1 answer:

adoni [48]3 years ago

3 0

Answer:

Step-by-step explanation:

c.d. d=8-3=5

$a_{n}=a_{n-1}+5$

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Rachel ordered early learning software for her daughter from an online retailer. Each item costs

andre [41]

Answer:

60$

Step-by-step explanation:

Shipping is 7.50 and the 7 items are 52.5 total

4 0

3 years ago

Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0

eduard

If you're using the app, try seeing this answer through your browser: brainly.com/question/2787701

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$\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}$

Square both sides:

$\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}$

$\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}$

Since $\mathsf{sin\,\theta}$ is positive, you can discard the negative sign. So,

$\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}$

Substitute this value back into $\mathsf{(i)}$ to find $\mathsf{cos\,\theta:}$

$\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

7 0

3 years ago

Write an expression that can be used to multiply 6x198 mentally

Vilka [71]

6×100+6×90+6×8 I think that is the answer

4 0

3 years ago

Read 2 more answers

Write a number that is the same when rounded to the nearest hundred and ten

inn [45]

202 because you can round it to 200

7 0

4 years ago

Find the range. 3 –9 7 –1 5 –4 2

grin007 [14]

Put in order from smallest to largest
–9, –4, –1, 2, 3, 5, 7

Minimum = –9<span>
Maximum = 7

</span>Range = 7 - (-9) = 7 + 9 = 16

Range = the difference between the maximum and minimum data values

hope it helps

7 0

3 years ago