If the mean of a negatively skewed distribution is 72, which of these values could be the median of the distribution?

Arranging like terms; solve the linear system using eliminationlly - 3x = 18- 3x = -16y + 33

DENIUS [597]

Solution

For this case we can do the following:

11y - 3x = 18

16y -3x = 33

We can multiply the first equation by -1 and we got:

-11y +3x =-18

16y -3x = 33

_______________

16y -11y = 33-18

5y = 15

y= 15/5 = 3

And then solving for x we got

x = -(18 -11*3)/ 3= -15/3 = 5

8 0

1 year ago

What is temperature of hot chocolate in degrees celsius?

olga55 [171]

Assuming it's boiling, the temperature will be 100°C, since water based materials can not exceed that without becoming a gas.

7 0

3 years ago

What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7 ?

jarptica [38.1K]

The answer is $\frac{2}{3}$

4 0

2 years ago

Read 2 more answers

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

Tomtit [17]

Apparently my answer was unclear the first time?

The flux of F across S is given by the surface integral,

$\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S$

Parameterize S by the vector-valued function r(u, v) defined by

$\mathbf r(u,v)=7\cos u\sin v\,\mathbf i+7\sin u\sin v\,\mathbf j+7\cos v\,\mathbf k$

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2. Then the surface element is

dS = n • dS

where n is the normal vector to the surface. Take it to be

$\mathbf n=\dfrac{\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}}{\left\|\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}\right\|}$

The surface element reduces to

$\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\mathbf n\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$