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Sholpan [36]
3 years ago
9

If the mean of a negatively skewed distribution is 72, which of these values could be the median of the distribution?

Mathematics
1 answer:
loris [4]3 years ago
4 0

Answer: the correct answer is 76

Step-by-step explanation:

(APEX)

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A scientist has started a bacteria culture with 1,000 cells. The cells will double every hour. 1. Write the sequence that repres
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Answer:

See below in bold.

Step-by-step explanation:

1.   The sequence is 1000, 2000, 4000, 8000.

2.  The common ratio  is 2000/1000 = 2.

3.   Number of bacteria after 7 hours is 1000(2)^(7- 1)

    = 64,000.

4.   1000(2)^(x-1)  > 1,000,000

2^x-1  > 1000

x- 1  log 2 > log 10

x- 1 > 9.96

x > 10.96

During the 11th hour.

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3 years ago
A pole is used to support an observation platform. The top of the pole is secured by two guy wires, one 18 and the other 21 feet
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Let A be the point on the ground to with the 18 foot guy is anchored and D the point on the ground to with the 21 foot guy is anchored.

We can conclude that the <span>the two wires at the points where they are anchored are 21 feet apart. Check the procedures in the picture attached.</span>

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2 years ago
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3 years ago
How can I find a?<br> (Trigonometric Ratios)
earnstyle [38]

Step-by-step explanation:

Hey there!

<u>Use</u><u> </u><u>cos</u><u> </u><u>ratio to</u><u> </u><u>find </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>'</u><u>a'</u><u>.</u>

As per given, we can state that it is a Right angled triangle, so taking 38° reference angle.

We get;

p = AC

b = 6

and h= a

Here, <u>Use</u><u> </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>b</u><u>,</u><u> </u><u>h</u><u> </u><u>and</u><u> </u><u>3</u><u>8</u><u>°</u><u> </u><u>angle</u><u> </u><u>to</u><u> </u><u>find</u><u> </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>a</u><u>.</u>

\cos(38° )  =  \frac{b}{h}

\cos(38°)  =  \frac{6}{a}

0.7881 =  \frac{6}{a} [ cos(38°=0.7881]

0.7881a = 6

a =  \frac{6}{0.7881}

Therefore the measure of a is 7.61 Or 8.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>

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