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Sholpan [36]
3 years ago
9

If the mean of a negatively skewed distribution is 72, which of these values could be the median of the distribution?

Mathematics
1 answer:
loris [4]3 years ago
4 0

Answer: the correct answer is 76

Step-by-step explanation:

(APEX)

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Arranging like terms; solve the linear system using eliminationlly - 3x = 18- 3x = -16y + 33
DENIUS [597]

Solution

For this case we can do the following:

11y - 3x = 18

16y -3x = 33

We can multiply the first equation by -1 and we got:

-11y +3x =-18

16y -3x = 33

_______________

16y -11y = 33-18

5y = 15

y= 15/5 = 3

And then solving for x we got

x = -(18 -11*3)/ 3= -15/3 = 5

8 0
1 year ago
What is temperature of hot chocolate in degrees celsius?
olga55 [171]
Assuming it's boiling, the temperature will be 100°C, since water based materials can not exceed that without becoming a gas.
7 0
3 years ago
What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7 ?
jarptica [38.1K]
The answer is \frac{2}{3}
4 0
2 years ago
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Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
Tomtit [17]

Apparently my answer was unclear the first time?

The flux of <em>F</em> across <em>S</em> is given by the surface integral,

\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S

Parameterize <em>S</em> by the vector-valued function <em>r</em>(<em>u</em>, <em>v</em>) defined by

\mathbf r(u,v)=7\cos u\sin v\,\mathbf i+7\sin u\sin v\,\mathbf j+7\cos v\,\mathbf k

with 0 ≤ <em>u</em> ≤ π/2 and 0 ≤ <em>v</em> ≤ π/2. Then the surface element is

d<em>S</em> = <em>n</em> • d<em>S</em>

where <em>n</em> is the normal vector to the surface. Take it to be

\mathbf n=\dfrac{\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}}{\left\|\frac{\partial\mathbf r}{\partial v}\times\frac{\partial\mathbf r}{\partial u}\right\|}

The surface element reduces to

\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\mathbf n\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv

\implies\mathbf n\,\mathrm dS=-49(\cos u\sin^2v\,\mathbf i+\sin u\sin^2v\,\mathbf j+\cos v\sin v\,\mathbf k)\,\mathrm du\,\mathrm dv

so that it points toward the origin at any point on <em>S</em>.

Then the integral with respect to <em>u</em> and <em>v</em> is

\displaystyle\iint_S\mathbf F\cdot\mathrm d\mathbf S=\int_0^{\pi/2}\int_0^{\pi/2}\mathbf F(x(u,v),y(u,v),z(u,v))\cdot\mathbf n\,\mathrm dS

=\displaystyle-49\int_0^{\pi/2}\int_0^{\pi/2}(7\cos u\sin v\,\mathbf i-7\cos v\,\mathbf j+7\sin u\sin v\,\mathbf )\cdot\mathbf n\,\mathrm dS

=-343\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}\cos^2u\sin^3v\,\mathrm du\,\mathrm dv=\boxed{-\frac{343\pi}6}

4 0
3 years ago
Suzanne bought 6 paint sets. Each set contains the same number of brushes. She has 18 brushes. Write and solve an equation to de
PSYCHO15rus [73]

Answer:

3

Step-by-step explanation:

Given that:

The number of paint sets, Suzanne bought= 6

As each set contains the same number of brushes.

Let x be the number of brushes each set contains.

So, the total number of brushes in 6 sets = 6x.

It is given that the total number of brushes she has is 18, which is equals to 6x.

So, the required equation is

6x=18

\Rightarrow x=\frac {18}{6}

\Rightarrow x=3.

Hence, the number of paint brushes each set contains is 3.

4 0
3 years ago
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