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3 years ago

7

Write the equation of the line in slope-intercept form that has: slope: -1 and point: (1, 1)

1 answer:

lara31 [8.8K]3 years ago

3 0

Answer:

f(x) = -1x + 1

Step-by-step explanation:

f(x) = mx + b

the equation above is slope intercept form. in order to make it you need a slope and a y intercept. you were given the slope, so now you need a y intercept. but where would you find that??? look no farther than the point you were given, (1,1). the y intercept is the second number in the parentheses. next you take your slope and your y-intercept and place them in.

f(x) = -1x + 1

hope i could help

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Please help solve this equation. Show all steps please. No links or files.

maksim [4K]

Answer:

See below

Step-by-step explanation:

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2 years ago

Figure ABCD is a square. Prove BD ≅ AC. Statements Reasons 1. ABCD is a square 1. given 2. ∠DAB, ∠ABC, ∠BCD, and ∠CDA are right

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yanalaym [24]

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3 years ago

Solve the inequality (3x+2)/(x+1)>4

Alex

$\dfrac{3x+2}{x+1}>4$
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3 years ago

Which equation represents a circle with the same radius as

sattari [20]

Answer :

$(x+1)^2+(y-1)^2=4^2$ and $(x+1)^2+(y-1)^2=16$

Step-by-step explanation:

Given : A circle with the same radius as the circle shown but with a center at (-1.1).

To find : Which equation represents a circle ?

Solution :

The equation of a circle with center (h,k) and radius r is given by :

$(x-h)^2+(y-k)^2=r^2$

Here, we are given (h,k)=(-1,1)

and radius r=4 units

So, equation of circle will be :

$(x-(-1))^2+(y-1)^2=4^2$

$(x+1)^2+(y-1)^2=4^2$

or $(x+1)^2+(y-1)^2=16$

Therefore, the required equations of circle are

$(x+1)^2+(y-1)^2=4^2$ and $(x+1)^2+(y-1)^2=16$

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3 years ago