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3 years ago

Find the length of the missing side. if necessary, round to the nearest tenth.

Mathematics

2 answers:

Flauer [41]3 years ago

5 0

What he said lol.....

Tcecarenko [31]3 years ago

3 0

the answer to this question would be c- 15.6

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Select the correct answer.<br> Which graph represents this equation?<br> 5y = x + 5

Naily [24]

Answer: the graph that passes through 0,1

Step-by-step explanation:

y=1/5x+1

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3 years ago

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On Mars, an object weighs 38% as much as on Earth. How much would a person who weighs 165 pounds on Earth weigh on Mars?

nikdorinn [45]

Answer:

62.7

Step-by-step explanation:

165 * 0.38 = 62.7

This is assuming you mean an object weights 38% less on mars then earth, if its the other way around(they weight 38% more on mars then earth) it would be,

165 * 1.38 = 227.7

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4 years ago

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Evaluate this expression if a = 2, b = -1 and c = 1.

labwork [276]

Substitute the values into the equation

2(2)+4(-1)-5(1)
4-4-5
-5

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3 years ago

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What is the Compound interest on a 10,000 investment the earns 6% compound monthlyfor5 years

Vlad1618 [11]

Answer:

The total compound interest is $3,488.50, I hope I helped explain how to find total compound interest

Step-by-step explanation:

So the formula for this would be:

A = P(1+r/n)^nt

A = the amount of your principal plus interest, which is the total

P = stands for the principal, which is your original amount invested

r = shows the interest rate in decimal form

n = stands for the number of compounding periods

So to solve for the compound interest we would plug in our numbers in replacement for the letters

8 0

3 years ago

A right circular cone is undergoing a transformation in such a way that the radius of the cone is increasing at a rate of 1/2 in

Ivenika [448]

Answer:

The volume is decreasing at the rate of 1.396 cubic inches per minute

Step-by-step explanation:

Given

Shape: Cone

$\frac{dr}{dt} =\frac{1}{2}$ --- rate of the radius

$\frac{dh}{dt} =-\frac{1}{3}$ --- rate of the height

$r = 2$

$h = \frac{1}{3}$

Required

Determine the rate of change of the cone volume

The volume of a cone is:

$V = \frac{\pi}{3}r^2h$

Differentiate with respect to time (t)

$\frac{dV}{dt} = \frac{\pi}{3}(2rh \frac{dr}{dt} + r^2 \frac{dh}{dt})$

Substitute values for the known variables

$\frac{dV}{dt} = \frac{\pi}{3}(2*2*\frac{1}{3}* \frac{1}{2} - 2^2 *\frac{1}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}* \frac{1}{2} - \frac{4}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}(\frac{1}{2} - 1))$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}*- 1)$

$\frac{dV}{dt} = -\frac{\pi}{3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{7*3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{21}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{88}{63}$

$\frac{dV}{dt} =-1.396in^3/min$

The volume is decreasing at the rate of 1.396 cubic inches per minute

3 0

3 years ago