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leonid [27]
2 years ago
6

PLEASE ANSWER WILL MARK BRAINLIEST TO FIRST ANSWER.

Mathematics
2 answers:
Inga [223]2 years ago
3 0

Answer:

60 I think

Step-by-step explanation:

125 + 115=240

240-180÷60

Sindrei [870]2 years ago
3 0

Answer:

60

Step-by-step explanation:

The measure of angle i : 60

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Prove that sin3a-cos3a/sina+cosa=2sin2a-1
Sloan [31]

Answer:

\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1

Step-by-step explanation:

we are given

\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1

we can simplify left side and make it equal to right side

we can use trig identity

sin(3a)=3sin(a)-4sin^3(a)

cos(3a)=4cos^3(a)-3cos(a)

now, we can plug values

\frac{(3sin(a)-4sin^3(a))-(4cos^3(a)-3cos(a))}{sin(a)+cos(a)}

now, we can simplify

\frac{3sin(a)-4sin^3(a)-4cos^3(a)+3cos(a)}{sin(a)+cos(a)}

\frac{3sin(a)+3cos(a)-4sin^3(a)-4cos^3(a)}{sin(a)+cos(a)}

\frac{3(sin(a)+cos(a))-4(sin^3(a)+cos^3(a))}{sin(a)+cos(a)}

now, we can factor it

\frac{3(sin(a)+cos(a))-4(sin(a)+cos(a))(sin^2(a)+cos^2(a)-sin(a)cos(a)}{sin(a)+cos(a)}

\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}

we can use trig identity

sin^2(a)+cos^2(a)=1

\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}

we can cancel terms

=3-4(1-sin(a)cos(a))

now, we can simplify it further

=3-4+4sin(a)cos(a))

=-1+4sin(a)cos(a))

=4sin(a)cos(a)-1

=2\times 2sin(a)cos(a)-1

now, we can use trig identity

2sin(a)cos(a)=sin(2a)

we can replace it

=2sin(2a)-1

so,

\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1


7 0
3 years ago
Read 2 more answers
Kris has finished 7/8 of 40 questions. how many were done​
VLD [36.1K]

7/8=0.875

0.875 x 40= 35

Therefore, Kris has finished 35 questions.

Hope this helps.

8 0
2 years ago
Which equations support the fact that rational numbers are closed under subtraction?
Illusion [34]

Answer:

A rational number is said to be closed if the subtracted values and the result obtained are rational. Hence, the equations which supports the condition are :

5.5 - 0.5 = 4

5√4 - √4 = 4√4

Step-by-step explanation:

A.)

√8 - √8 = 0 ; the added values aren't rational and the result, Zero is not rational either.

B.)

5√4 - √4 = 4√4

5(2) - 2 = 2(2)

10 - 2 = 4

All the values in the expression are rational ; hence, it supports the assertion.

C)

5.5 - 0.5 = 4 ; all the values in the expression are rational, hence, it supports the fact.

2√3 - √3 = √3 ; the values in the expression are not rational, hence, it does not meet the condition.

Therefore, only options B and C supports the assertion.

Let me add that I learned most of this from Brainly a user named fichoh :)

7 0
2 years ago
Which ordered pairs are a solution to the equation:
denpristay [2]
The first and the second
4 0
2 years ago
Which of the following numbers is a rational but not a integer
Temka [501]
Rational numbers are numbers that can be turned into a fraction. They can be negative or positive.
Integers are whole numbers. They can be negative or positive. 

Numbers such as 0.10 are rational because they can be turned into a fraction
0.10 = 1/10....and since it is not a whole number, it is not an integer.
8 0
2 years ago
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