Answer:
50 dollors
Step-by-step explanation:
Answer:
23
Step-by-step explanation:
Brackets go first, 5 (y) - 4 (x) = 1. Now, 3 x 1 = 3, you do this because of the 3 next to the brackets. Now add them together.
Answer:
<em>y = - cos ( </em>
<em> x + </em>
<em> ) </em>
Step-by-step explanation:
y = A cos ( Bx + C) + D
Vertical shift D = 0
A = - 1
Compression / Stretching B
Period of given function is
Period of cos x is 2π
=
⇒ B =
Horizontal shift is C ÷ B
Horizontal shift of given function is
= C ÷
⇒ C =
So, the equation of given function is
<em>y = - cos ( </em>
<em> x + </em>
<em> ) </em>
The sum of squares of numbers is: 13
Step-by-step explanation:
Let x and y be two numbers
Then,
Difference of the squares of the numbers will be:

Product will be:

Given identity is:

Given values are:
Difference of the squares of the numbers=
Product of numbers = xy = 6
Putting the values in the identity
![(x^2+y^2)^2=(5)^2+[2(6)]^2\\=25+(12)^2\\=25+144\\=169](https://tex.z-dn.net/?f=%28x%5E2%2By%5E2%29%5E2%3D%285%29%5E2%2B%5B2%286%29%5D%5E2%5C%5C%3D25%2B%2812%29%5E2%5C%5C%3D25%2B144%5C%5C%3D169)
As we have to only find x^2+y^2
Taking square root on both sides

The sum of squares of numbers is: 13
Keywords: Identities
Learn more about identities at:
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Answer:
The chance of getting exactly 3 hits is = 0.20
Step-by-step explanation:
P.S - The exact question is -
As given,
F(x) = 0 , x < 1
0.30 , 1 ≤ x < 2
0.56 , 2 ≤ x < 3
0.76 , 3 ≤ x < 4
0.9 , 4 ≤ x < 5
1 , 5 ≤ x
Now,
f(x) = 0.30 , x = 1
0.56 - 0.30 = 0.26 , x = 2
0.76 - 0.56 = 0.20 , x=3
0.9 - 0.76 = 0.14 , x = 4
1 - 0.9 = 0.1 , x = 5
0, otherwise
Now,
The chance of getting exactly 3 hits is = f(x = 3) = 0.20