Help me please , I’m stuck and i don’t know what to do
1 answer:
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Hey There!! ~
The answer to this is: the upper bound for the length is Lower and Upper Bounds
The lower bound is the smallest value that will round up to the approximate value.
The upper bound is the smallest value that will round up to the next approximate value.
Ex:- a mass of 70 kg, rounded to the nearest 10 kg, The upper bound is 75 kg, because 75 kg is the smallest mass that would round up to 80kg.
Here , A length is measured as 21cm correct to 2 significant figures. We need to find what is the upper bound for the length . let's find out:
As discussed above , upper bound for any number will be the smallest value in decimals which will round up to next integer value . So , for 21 :
⇒
21.5 cm on rounding off will give 22 cm . So , the upper bound for the length is
Hope It Helped!~
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The length of one side is 12√3.
We know that the area of a triangle is given by the formula:
A=1/2(b)(h)
We can substitute the area in:
108√3 = 1/2(b)(h)
Let b be the side of the equilateral triangle. To find the height, we will use the Pythagorean theorem. We know that the height bisects the base, so we will call that leg of the right triangle formed (1/2b). Since the triangle is equilateral, we will call the hypotenuse b as well. We now have:
We will now substitute this in the formula for area we had above:
108√3=(1/2)(b)(√3/2b)
108√3=√3/4b²
Multiply both sides by 4:
(108√3)×4=(√3/4b²)×4
432√3=√3b²
Divide both sides by √3:
432√3/√3 = √3b²/√3
432=b²
Take the square root of both sides:
√432=√b²
Simplifying the radical, we have 12√3.
We know that the area of a triangle is given by the formula:
A=1/2(b)(h)
We can substitute the area in:
108√3 = 1/2(b)(h)
Let b be the side of the equilateral triangle. To find the height, we will use the Pythagorean theorem. We know that the height bisects the base, so we will call that leg of the right triangle formed (1/2b). Since the triangle is equilateral, we will call the hypotenuse b as well. We now have:
We will now substitute this in the formula for area we had above:
108√3=(1/2)(b)(√3/2b)
108√3=√3/4b²
Multiply both sides by 4:
(108√3)×4=(√3/4b²)×4
432√3=√3b²
Divide both sides by √3:
432√3/√3 = √3b²/√3
432=b²
Take the square root of both sides:
√432=√b²
Simplifying the radical, we have 12√3.