I've attached the complete question.
Answer:
Only participant 1 is not cheating while the rest are cheating.
Because only participant 1 has a z-score that falls within the 95% confidence interval.
Step-by-step explanation:
We are given;
Mean; μ = 3.3
Standard deviation; s = 1
Participant 1: X = 4
Participant 2: X = 6
Participant 3: X = 7
Participant 4: X = 0
Z - score for participant 1:
z = (x - μ)/s
z = (4 - 3.3)/1
z = 0.7
Z-score for participant 2;
z = (6 - 3.3)/1
z = 2.7
Z-score for participant 3;
z = (7 - 3.3)/1
z = 3.7
Z-score for participant 4;
z = (0 - 3.3)/1
z = -3.3
Now from tables, the z-score value for confidence interval of 95% is between -1.96 and 1.96
Now, from all the participants z-score only participant 1 has a z-score that falls within the 95% confidence interval.
Thus, only participant 1 is not cheating while the rest are cheating.
Well,
it says The quatient of x and seven is 5 more than three times x
The quotient = x/7
three times x = 3x
x/7 = 3x + 5 This is the answer
The given question is incomplete. The complete question is:
A farmer sells 9.9 kg of pears and apples at the farmers market. 3/4 of this weight is pears,and the rest is apples.how many kilograms of apples did she sell at the farmers market.
Answer: The farmer sells 2.475 kg of apples.
Step-by-step explanation:
Given : Total weight of pears and apples = 9.9 Kg
of the total weight is pears
Hence, weight of pears =
Therefore weight of apples = Total weight - weight of pears = (9.9 -7.425) = 2.475 Kg
We've hit on a case where a measure of center does not provide all the information spread or variability there is in month-to-month precipitation. based on how busy each month has been in the past, lets managers plan
$8.30?
I need more info, is this including tax or are you having to tax the items as well?