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Blizzard [7]
3 years ago
7

Maylin goes to her local sporting goods store to buy socks and jogging shorts. Socks cost​ $10 per pair and jogging shorts cost​

$15 each. At her current consumption bundle pair of 4 pairs of socks and 2 jogging​ shorts, her marginal benefit from the last pair of socks is 20 and the marginal benefit of the last jogging short is 30. Maylin should​ ________.
Mathematics
1 answer:
PolarNik [594]3 years ago
5 0

Answer:

Maylin should purchase one unit of each socks & jogging shorts.

Step-by-step explanation:

In case of two goods, consumer is at equilibrium when marginal utility per dollar spent on last unit of the goods are equal, ie MU 1 / P1 = MU 2 / P2 (MU are the marginal utilities / marginal benefit of two goods, P are the price of two goods)

Given : MU1 (So) = 20, MU2 (JSh)  = 30, P1 (So) = 10, P2 (JSh) = 15

So, equilibrium is at where MU1 (So) / P1 (So) = MU2 (JSh) / P2 (Jsh)

20/10 = 2, & 30/15 = 2.  MU's per dollar are equal for both.

So Maylin is in equilibrium, she should purchase one unit of each socks & jogging shorts.

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Convert. <br><br><br> 56/100<br><br><br> 0.7:
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Help appreciated on question in image!<br> Thanks:)
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x=-1,\:x=-7,\:x=i,\:x=-i

Step-by-step explanation:

Considering the equation

x^4+8x^3+8x^2+8x+7=0

Solving

x^4+8x^3+8x^2+8x+7

\mathrm{Factor\:}x^4+8x^3+8x^2+8x+7:\quad \left(x+1\right)\left(x+7\right)\left(x^2+1\right)

As

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=7,\:\quad a_n=1

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:7,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:7}{1}

-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1

=\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]

Solving

\frac{x^4+8x^3+8x^2+8x+7}{x+1}

=x^3+7x^2+x+7

Putting \frac{x^4+8x^3+8x^2+8x+7}{x+1} =  x^3+7x^2+x+7 in equation [A]

So,

\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]

=\left(x+1\right)x^3+7x^2+x+7

As

x^3+7x^2+x+7=\left(x+7\right)\left(x^2+1\right)

So,

Equation [A] becomes

=\left(x+1\right)\left(x+7\right)\left(x^2+1\right)

So,  the polynomial equation becomes

\left(x+1\right)\left(x+7\right)\left(x^2+1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)\mathrm{Solve\:}\:x+1=0:\quad x=-1

\mathrm{Solve\:}\:x+7=0:\quad x=-7

\mathrm{Solve\:}\:x^2+1=0:\quad x=i,\:x=-i

\mathrm{The\:solutions\:are}

x=-1,\:x=-7,\:x=i,\:x=-i

Keywords: polynomial equation

Learn polynomial equation from brainly.com/question/12240569

#learnwithBrainly

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