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3 years ago

Two-thirds a number less than four is negative seven.

Mathematics

1 answer:

zhuklara [117]3 years ago

8 0

4 - 2/3x = -7 would be the equation to represent this.

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Given A = {1, 3, 5, 7, 9}, B = {2, 4, 6, 8, 10}, C = {1, 5, 6, 7, 9}

andrey2020 [161]

Answer:

ummmm thats not even a question

Step-by-step explanation:

6 0

2 years ago

C+4c=15 what’s the answer?

Fynjy0 [20]

C=3 that’s the answer I think

4 0

2 years ago

Which equation represents the cross products?

AleksAgata [21]

the answer will be A. its the right answer

4 0

3 years ago

Help would be much appreciated pic of question

Westkost [7]

Answer:

see attached

Step-by-step explanation:

The graph is a series of horizontal lines. A solid dot goes wherever there is an "or equal to" symbol in the inequality. An open dot goes where the point is not included in the function definition (but nearby points are).

7 0

2 years ago

A 555-mile, 5-hour plane trip was flown at two speeds. For the first part of the trip, the average speed was 105 mph. Then the t

Pepsi [2]

Answer:

Hence Distance traveled at speed 115 mph is 345 miles and Distance traveled at speed 105 mph is 210 miles.

Step-by-step explanation:

Given:

Total Distance = 555 mile

Total time = 5 hour

Let time taken to travel at 115 mph be t

So Time taken to travel at 105 mph will be equal to difference between Total time and time taken to travel at 115 mph.

Time taken to travel at 105 mph = $5-t$

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 115 mph = $115t$

Also;

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 105 mph = $105(t-5) = 105t - 525$

Now Total Distance traveled is equal sum of Distance traveled in 115 mph and Distance traveled in speed 105 mph

$115t-(105t-525)=555\\\\115t-105t+525=555\\\\10t+525=555\\\\10t=555-525\\\\10t=30\\\\t=\frac{30}{10}=3$

Time taken to travel at 115 mph = 3 hrs.

Time taken to travel at 105 mph = $5-t=5-3=2\ hrs$

Now Distance traveled in 115 mph = $115t = 115 \times 3 = 345\ miles$

Distance traveled in 105 mph = $105(5-t) = 105(5-3)= 105\times 2 = 210\ miles$

Hence Distance traveled at speed 115 mph is 345 miles and Distance traveled at speed 105 mph is 210 miles.

6 0

2 years ago