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Stella [2.4K]
3 years ago
9

What is the approximate area of the circle shown below?

Mathematics
2 answers:
creativ13 [48]3 years ago
4 0
Area = pi * radius²
Area = 3.14159 * 9²
Area = 3.14159 * 81
Area = <span> <span> <span> 254.46879 </span> </span> </span>
answer is D


mixas84 [53]3 years ago
4 0

Answer: The correct option is D.

Explanation:

From the given figure it is noticed that the point C is the center of the circle and the length of the diameter is 18 cm.

We know the diameter is twice of the radius,

2r=d

2r=18

r=9

Therefore, the radius of the circle is 9 cm.

The formula to find the area of the circle is,

A=\pi r^2

A=\pi (9)^2

A=\pi (81)

A=254.469\approx 254

Therefore, the D is the correct option. The area of the circle is 254 cm square.

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Which ordered pair is in the solution set of the system of linear inequalities? y &gt;3/2 x – 1 y &lt;3/2 x – 1 (–5, 2) (2, 2) (
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Answer:

No solution

Option 4 is correct

Step-by-step explanation:

Given: The system of inequality

y>\dfrac{3}{2}x-1

y

We need to choose correct option.

Option 1: (-5,2)

Put x=-5 and y=2

Equation 1                               Equation 2

2>\dfrac{3}{2}(-5)-1                            2

2>-8.5                                    2

    TRUE                                     FALSE

Option 2: (2,2)

Put x=2 and y=2

Equation 1                              Equation 2

2>\dfrac{3}{2}(2)-1                    2

2>2                                           2

  FALSE                                      FALSE

Option 3: (5,2)

Put x=-5 and y=2

Equation 1                            Equation 2

2>\dfrac{3}{2}(5)-1                      2

2>6.5                                           2

 FALSE                                      TRUE

Option 1, 2 and 3 are incorrect because both equation must be true for solution.

Hence, Option 4 is correct no solution.  

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Step-by-step explanation:

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The 6 terms of the series are

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Put the following equation in standard form and determine the quadratic, linear, and constant coefficients. -3x2 - 8 = 5x - 7
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Answer:

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  • -3 (quadratic)
  • -5 (linear)
  • -1 (constant)

Step-by-step explanation:

The equation will be in standard form when terms are listed in order of decreasing degree, and the right side of the equation is 0.

<h3>Standard form</h3>

We can subtract the right-side expression from both sides to get standard form.

  -3x² -8 -(5x -7) = 5x -7 -(5x -7)

  -3x² -8 -5x +7 = 0 . . . . . . . simplify a bit

  -3x² -5x -1 = 0 . . . . . . . . . collect terms

The standard form equation can be written ...

  -3x² -5x -1 = 0

<h3>Coefficients</h3>

The quadratic coefficient is the coefficient of the term with degree 2. The quadratic coefficient is -3.

The linear coefficient is the coefficient of the term with degree 1. The linear coefficient is -5.

The constant coefficient is the coefficient of the term with no variables. The constant is -1.

__

<em>Additional comment</em>

We can make the leading coefficient positive by multiplying the equation by -1. This gives ...

  3x² +5x +1 = 0

with quadratic, linear, and constant coefficients 3, 5, 1.

This is a legitimate answer to this question. In the case of linear equations, the "standard form" has the constant on the right side of the equal sign, and the leading coefficient is required to be positive. A negative leading coefficient can sometimes lead to errors (when the sign is overlooked), so having a positive leading coefficient is often preferred.

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