Answer:
-3
Step-by-step explanation:
The graph goes down 3 for each one on the x-axis
Answer:
25.1 inches
Step-by-step explanation:
Radius of the circle = 4 inches
We have to calculate the value of Circumference of the circle.
The formula to calculate the circumference is:
Circumference = 2πr
We have to use π = 3.14, as said in the question:
So using the values, we get:
Circumference = 2 x 3.14 x 4 = 25.12 inches
Number of decimals in radius is zero, so we have to round the answer to one decimal place as said in the question.
Therefore, the circumference of the circle rounded to one decimal place will be 25.1 inches
When you multiply, you are often making a comparison between two numbers.
Answer:
x = 2, y = 3
Step-by-step explanation:
x + y = 5
Shift y to the other side and change to (-y).
x = 5 - y --- Equation 1
x - 2y = -4 --- Equation 2
Substitute x = 5 - y into Equation 2:
x - 2y = -4
5 - y - 2y = -4
Shift 5 to the other side and change to (-5).
-y - 2y = -4 - 5
Evaluate like terms.
-3y = -9
Divide both sides by -3.
y = -9 ÷ -3
y = 3
Substitute y = 3 into Equation 1:
x = 5 - y
x = 5 - 3
x = 2
Yes, this is a right triangle. B'(-2,0)
1) Given those coordinates let's plot that triangle:
Let's find the legs:
![\begin{gathered} d_{AC}=\sqrt[]{(8-2)^2+(-5-3)^2}=10 \\ d_{BC}=\sqrt[]{(8-6)^2+(-5-6)^2}=5\sqrt[]{5} \\ d_{AB}=\sqrt[]{(6-2)^2+(6-3)^2}=5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20d_%7BAC%7D%3D%5Csqrt%5B%5D%7B%288-2%29%5E2%2B%28-5-3%29%5E2%7D%3D10%20%5C%5C%20d_%7BBC%7D%3D%5Csqrt%5B%5D%7B%288-6%29%5E2%2B%28-5-6%29%5E2%7D%3D5%5Csqrt%5B%5D%7B5%7D%20%5C%5C%20d_%7BAB%7D%3D%5Csqrt%5B%5D%7B%286-2%29%5E2%2B%286-3%29%5E2%7D%3D5%20%5Cend%7Bgathered%7D)
Let's test whether this is or not a Right Triangle, by using the Pythagorean Theorem:
![\begin{gathered} (5\sqrt[]{5})^2=10^2+5^2 \\ 125=100+25 \\ 125=125\text{ TRUE} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%285%5Csqrt%5B%5D%7B5%7D%29%5E2%3D10%5E2%2B5%5E2%20%5C%5C%20125%3D100%2B25%20%5C%5C%20125%3D125%5Ctext%7B%20TRUE%7D%20%5Cend%7Bgathered%7D)
Hence, this is a right triangle.
b) Reflecting that triangle across leg AC, we have:
Counting to the left of Vertix A, 2 units to the left we have the Vertix B' and since its a reflection across AC, A = A' and C=C'
Therefore
B'(-2,0)
